Question

Class 250 Print Reading for Industry Name Date Industry Print Exercise 12-1 Refer to the print PR 12-1 and ansaver the questions belore 1. How many surface texture symbols are there on the views of this drawing? r to the axis of this part that have surface texture s microinches or s should have a surface texture of 3. For the surface texture symbols that have a horizontal bar, what does the .05 indicate? 4. According to the lay symbols shown in the round view, should the lay on the two flat the same direction as the axis of the cylinder or perpendicular to the axis? 5. What surface texture value should be applied to all surfaces not specified on the drawing views Review questions based on previous units 6 What scale are the views on the original drawing for this print? 7 For the fractional dimensions, what tolerances should be applied? 8. What is the part name? 9. Are there any section lines on this drawing? 10. What type of section view is used in this drawing? 11. What is the pitch of the external thread? 12. How are the threads represented? Why is the countersink hole on the right end not dimensioned? 13. 14. There is a limit-method dimension labeled P.D. What does P.D. stand for? 15. What is the MMC of the counterbore diameter?

Answer 1

1. Four (Two each on both views)

2. 32

3. Roughness sampling length

4. The lay indicated must perpendicular to the indicated lines i.e.perpendicular to the paper. The axis is also perpendicular to the paper hence the lay will be parallel to the axis of the cylinder

5. 63 microinches or smoother (See title block first note)

6. 1:1 (since full is mentioned in the scale)

7. +/- 1/64 (See title block second note)

8. RAM ADAPTER FOR 2 STRIP 40 CAVITY MOLD

9. No

10. Partial sectional view

11. The threads per inch of the thread is 12

The pitch will be 1/12=0.0833 inch

12. It is a simplified representation which uses visible and hidden lines to represent the major and minor diameters.

14. Pitch diameter of the thread

15. Adding the nominal and upper tolerance values

.7501+.0005=.7506