h1 = 338.14 KJ/Kg
h2 = 382 KJ/Kg
h3 = h4 = 243.15 KJ/Kg
Refrigeration effect (RE) = h1 - h4 = 338.14 - 243.15 = 94.99 KJ/Kg
Work Input to the system (W) = h2 - h1= 382 - 338.14 = 43.86 KJ/Kg
COP = RE / W = 94.99 / 43.86 = 2.166
In an ideal Vapor Compression Refrigeration Cycle,using h2=382 kJ/kg, h3=243.15 kJ/kg, h4=243.15 kJ/kg and h1=338.14 kJ/kg,...
In an ideal Vapor Compression Refrigeration Cycle,using h2=382 kJ/kg, h3=243.15 kJ/kg, h4=243.15 kJ/kg and h1=338.14 kJ/kg, determine the refrigerating effect in kJ/kg and coefficient of performance.
3.In an ideal Vapor Compression Refrigeration Cycle, using h2=382 kJ/kg, h3=243.15 kJ/kg, h4=243.15 kJ/kg and h1=338.14 kJ/kg, determine the refrigerating effect in kJ/kg and coefficient of performance.
2.A rotary type compressor compresses air from 98kPaa, 27C through a compression ratio of 5 and compression efficiency of 75%, find the compressor work. 3.In an ideal Vapor Compression Refrigeration Cycle,using h2=382 kJ/kg, h3=243.15 kJ/kg, h4=243.15 kJ/kg and h1=338.14 kJ/kg, determine the refrigerating effect in kJ/kg and coefficient of performance.
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Ammonia flows at 250 kg/s through an ideal vapor-compression refrigeration cycle. The ammonia enters the compressor as saturated vapor at-10°C and exits the condenser as saturated liquid at 1000 kPa. Determine the: (a) refrigerant temperature leaving the compressor (b) refrigerant temperature leaving the condenser (c) refrigerant temperature leaving the expansion valve (d) coefficient of performance (e) refrigeration capacity, in tons.
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