Find the position function x(t) of a moving particle with the given acceleration a(t), initial position...

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Find the position function x(t) of a moving particle with the given acceleration a(t), initial position Xo = x(0), and initia

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Answer 1

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act)= 4 (L+39 - 4 CLP+6L+9) act) = 448 +244 +36 vcto_ Sacks de SCALP+242 +36) dhe 3 36€ + c + + 4€ 24 € 4 t + I2LP +36€ + -4. 3 X(L) = L4 +4E+ 1848-42+g ty xco=2 -> a=2 ans) XCE) L4 +4E +4 t +18L-4tta 3 ans) x(t)=t⁴/3+4t³+18t²-4t+2

here we integrate accelecration a(t) to find v(t),then we apply initial condition v(0)=-4 to find integration constant.

then we integrate v(t) to find x(t).then we apply x(0)=2 to find integration constant.

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Answer 2

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