Question

PART B (12 points): Show your work and the steps clearly as possible on A concave mirror (R = 56.0 cm) is used to project a transparent slide onto a wall. The slide is located at a distance of 31.0 cm from the mirror, and a small flashlight shines light through the slide and onto the mirror. a) How far from the wall should the mirror be located? b) The height of the object on the slide is 0.95 cm. What is the height of the image? c) How should the slide be oriented, so that the picture on the wall looks normal Equations: M = h'/h = .ap 1/p + 1/9 = 2/R or 1/p + 1/4 - 1/1

Answer 1

location so that we - 28 cm 1 V 28 Solo: Wall should to placed at image can find the projection of object on the wall. Using Sign Conversions, ay U=-31com f = P/= the pet g 28 2 - 1 » v=-289.33c.m. that wall should be placed at distance 289.33 com from the wall or 2.89 m from the wall. m = b = -1 V b) 289-33 no 31 289.33 0.95 31 his. = -8.87om Thi=8.870.m. negative sign suggests that image inverted So 2 produces e Concave mirror inverted image of sirde on the wall so if slide itself is placed /oriented inverted, a Normal image of slide Can be found on the wall. slide is oriented inverted at 31com from the mirror to get normal image on the Well at 289m.