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Chapter -25 The Reflection of Light: Mirrors 3 - A coin is placed in front of a concave mirror that has a radius of curvature
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Answer #1

Since the magnification is equal tk the ratio of either the image height to the object height or also equal to the ratio of the image distance to the object distance from the mirror. So, object height/image height =5 = image distance/object distance.

Now R=0.5 so object distance will be 0.5/5=0.1 m

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