Question

and placed 12.2 cm in front of a mirror. A real and inverted 3. An object is 3.62 cm high and placed 12.2 cm in In mage of height - 2.00 cm is formed, (a) Would a concave or convex to form this image? Mathematically prove this answer. (b) W curvature of this mirror? is answer. (b) What is the radius of

Answer 1

here,

the height of object , ho = 3.62 m

the height of image , hi = -2 cm

the magnification, m = hi/ho

m = - 2 /3.62 = - 0.552

the object distance , do = 12.2 cm

the image distance ,di = - m * do

di = 6.74 cm

let the focal length be fu

using the mirror formula

1/f = 1/di + 1/do

1/f = 1/12.2 + 1/6.74

solving for f

f = 4.34 cm

as the focal length is positive

the mirror used is CONCAVE MIRROR

b)

the radius of curvature , r = 2f

r = 2 * 4.34 cm = 8.68 cm