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Two blocks are connected by a massless string over a pulley. Block 1 has mass mi=20kg and is on horizontal table Block 2 has

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we have mi=20kg, m2= lokg a 0 = 300 we have h mr =no e hallino = { [0=300 l=40m Initially ma da H (say) h tm. @ Ineteal mechloren reaches bottom ma Ef= kelift Urg KEzftUstk Epulley, f. = time?+ might & malet magxo+& Iw? we have I- Mr2 Ef=kmiut mighto for mi a T 1 . TiE m, a mig IL Ti 온 pulley (Т. -17 ) = 14 - r- < W Ч: Hz лу = Т2 -ту ма [Yes) Кем. for me А) magino - Tz =

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