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Questions #4-5: consider the circuit below: 10012 W- E = 10 V 4. A real ammeter with an internal resistance of 1.0 2 is conne

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4) when ammeter is properly connected, the effective resistance of the circuit increases and hence the current through the circuit decrease. Now we know that power of batter = V × current,

So If current is decreased, then power of the battery will also DECREASE.

5) when we connect the voltmeter in the circuit, the effective Resistance of the circuit decreases , and hence the current increases which ultimately result in the INCREASE of power of the battery.

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