Homework Answers
Answer- In series with (D)
Reason- While measuring current,the probes of the ammeter should be placed in series with the component.It is so because in series the current remains same through out the circuit.It does not matter the component is adjacent or far from the component,as long as it is in series with the current and component.
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the component To measure current using a ammeter the probes of the meter would be placed...
the component To measure voltage using a digital multimeter the probes of the meter would be...
the component To measure voltage using a digital multimeter the probes of the meter would be placed O A. Parallel OB. Adjacent O C.Perpendicular OD. Tangent
Exercise 2. An instrument used to measure current is called an ammeter. The ammeter is connected...
Exercise 2. An instrument used to measure current is called an ammeter. The ammeter is connected into a circuit in series in the loop in which the desired current reading is required. The resistance of an ideal ammeter is zero, and it is essential in real ammeters that the resistance of the instrument be very small compared to other resistances in the circuit. Why? R2 Ri a)-A meter to measure potential difference is called a voltmeter. To find the potential...
QUESTION 11 When measuring current, the ammeter must be connected: O A. Could be either way...
QUESTION 11 When measuring current, the ammeter must be connected: O A. Could be either way B. In series with the component OC. None of the choices are correct OD. Could be connected either way only if you have a digital multimeter OE. In parallel with the component QUESTION 12 Power gain of 1000000 is: A. None of the other choices are correct B. 60 dB C. 20 dB D.30 dB E. 1000 dB
2. (Short Circuits) An Ammeter is a device that can measure current through a circuit compo-...
2. (Short Circuits) An Ammeter is a device that can measure current through a circuit compo- nent. It is devised to be a device that has a VERY LOW internal resistance r. You use the device by connecting the device in series with the branch of the circuit you want to measure the current through. Suppose you accidentally connected the ammeter in parallel with a bat- tery and another resistor (with resistance R»r). Using Kirchoff's rules, show that when s...
To measure the current through one branch of a parallel circuit, the meter is connected ________....
To measure the current through one branch of a parallel circuit, the meter is connected ________. Group of answer choices across the source in parallel with the branch resistor in series with the source in series with the branch resistor
Question One: In the figure below, what is the reading on the ammeter in each case...
Question One: In the figure below, what is the reading on the ammeter in each case .5 .6 (A) If you connected the circuit to the 3A setting on the ammeter, then the reading will be (B) If you connected the circuit to the 1A setting on the ammeter, then the reading will be (C) If you connected the circuit to the 300 mA setting on the ammeter, then the reading will be uestion Two: (A) Is the equivalent resistance,...
Would the answer be A? 9. An ammeter does not apprecby l curent of the circuit...
Would the answer be A?
9. An ammeter does not apprecby l curent of the circuit it is placed in because it is connected in series and has a low resistance y it is connected in parallel and has a high resistance it is connected in parallel and has a low resistance D) it is connected in series and has a high resistance it is connected in either series or parallel and has no resistance
(5) Using the d'Arsonval ammeter shown, design an ammeter to read a full-scale current reading of...
(5) Using the d'Arsonval ammeter shown, design an ammeter to read a full-scale current reading of 50 mA. R 50 mV A 2 mA Ammeter Use the meter in the circuit below to determine the current io in the 120 Ω resistor 210 Ω 280 Ω lo 30 mA(t) 200 Ω 120 Ω 18052
I need answer for these questions Record the ammeter current. Reverse the current (and the ammeter)...
I need answer for these questions
Record the ammeter current. Reverse the current (and the ammeter) and adjust the resist deflects exactly 45 degree on the opposite side of the magnetic meridian. Record the current currents and calculate, using the theoretical formula for the magnetic field at the center horizontal component of the earth's magnetic field. Determination of the vertical component of the earth's magnetic field and the total. Set the dipping needle's plane along the magnetic meridian and measure...
!? Verify Kirchhoff’s Current law (I) in = (I) out for junction point “X” in the...
!? Verify Kirchhoff’s Current law (I) in = (I) out for
junction point “X” in the circuit
point 560 Ω resistor 1000 Ω resistor 4.5 . 1 |ー オー1 ered battery box1 -T 10000 Ω resistor 17 black 1 Is switch (closed for measurements only) +1 To measure each current, the wire it is flowing through must be "cut" (disconnected) and the ammeter inserted in series. COM Do not place the ammeter across a component, as this may damage the...
the component To measure voltage using a digital multimeter the probes of the meter would be placed O A. Parallel OB. Adjacent O C.Perpendicular OD. Tangent
Exercise 2. An instrument used to measure current is called an ammeter. The ammeter is connected into a circuit in series in the loop in which the desired current reading is required. The resistance of an ideal ammeter is zero, and it is essential in real ammeters that the resistance of the instrument be very small compared to other resistances in the circuit. Why? R2 Ri a)-A meter to measure potential difference is called a voltmeter. To find the potential...
QUESTION 11 When measuring current, the ammeter must be connected: O A. Could be either way B. In series with the component OC. None of the choices are correct OD. Could be connected either way only if you have a digital multimeter OE. In parallel with the component QUESTION 12 Power gain of 1000000 is: A. None of the other choices are correct B. 60 dB C. 20 dB D.30 dB E. 1000 dB
2. (Short Circuits) An Ammeter is a device that can measure current through a circuit compo- nent. It is devised to be a device that has a VERY LOW internal resistance r. You use the device by connecting the device in series with the branch of the circuit you want to measure the current through. Suppose you accidentally connected the ammeter in parallel with a bat- tery and another resistor (with resistance R»r). Using Kirchoff's rules, show that when s...
Question One: In the figure below, what is the reading on the ammeter in each case .5 .6 (A) If you connected the circuit to the 3A setting on the ammeter, then the reading will be (B) If you connected the circuit to the 1A setting on the ammeter, then the reading will be (C) If you connected the circuit to the 300 mA setting on the ammeter, then the reading will be uestion Two: (A) Is the equivalent resistance,...
Would the answer be A?
9. An ammeter does not apprecby l curent of the circuit it is placed in because it is connected in series and has a low resistance y it is connected in parallel and has a high resistance it is connected in parallel and has a low resistance D) it is connected in series and has a high resistance it is connected in either series or parallel and has no resistance
(5) Using the d'Arsonval ammeter shown, design an ammeter to read a full-scale current reading of 50 mA. R 50 mV A 2 mA Ammeter Use the meter in the circuit below to determine the current io in the 120 Ω resistor 210 Ω 280 Ω lo 30 mA(t) 200 Ω 120 Ω 18052
I need answer for these questions
Record the ammeter current. Reverse the current (and the ammeter) and adjust the resist deflects exactly 45 degree on the opposite side of the magnetic meridian. Record the current currents and calculate, using the theoretical formula for the magnetic field at the center horizontal component of the earth's magnetic field. Determination of the vertical component of the earth's magnetic field and the total. Set the dipping needle's plane along the magnetic meridian and measure...
!? Verify Kirchhoff’s Current law (I) in = (I) out for
junction point “X” in the circuit
point 560 Ω resistor 1000 Ω resistor 4.5 . 1 |ー オー1 ered battery box1 -T 10000 Ω resistor 17 black 1 Is switch (closed for measurements only) +1 To measure each current, the wire it is flowing through must be "cut" (disconnected) and the ammeter inserted in series. COM Do not place the ammeter across a component, as this may damage the...
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