When 1.60 10 J of heat transfer occurs into a meat pie initially at 19.5 °C,...

Question

Question

When 1.60 10 J of heat transfer occurs into a meat pie initially at 19.5 °C, its entropy increases by 467 J/K. Estimate the f

Answer 1

Answer #1

Entropy change, $\Delta S = \frac{ Q}{\Delta T} = \frac{ Q}{T_f -T_i}$

Temp. rise, $T_f -T_i = \frac{ Q}{\Delta S}$

New Temp. $T_f = \frac{ Q}{\Delta S} +T_i$

$\Rightarrow T_f = \frac{ 1.60* 10^5}{467} +19.5 = 362.11^o C \rightarrow Answer$

Answer 2

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