When 1.65 x 105 J of heat transfer occurs into a meat pie initially at 20.0°c,...

Question

Question

When 1.65 x 105 J of heat transfer occurs into a meat pie initially at 20.0°c, its entropy increases by 470 J/K. What is its

Answer 1

Answer #1

i Info da = 1.65 X 105 Ti = 20°c = 20+2 73 = 293k ds = 470 JK change in entropy ds- da tusla T-T + ds = dax2 Ty +T; 470 - 1.6

Answer 2

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