Question

6. A 0.500kg glass (c=840 J/kg°C) containing 1.00L of water (at 20.0°C) is filled with 0.100kg of ice (initially at -5.0°C). a. What is the mass of the liquid water initially in the glass? b. What is the equilibrium temperature of the water and glass when all of the ice has melted? Ignore any heat gained from or lost to the surroundings. C. A person then drinks all of the water in the glass. How much heat is gained by the water as its temperature increases to 37.0°C in the digestive tract of the person?

Answer 1

water ci) Mass of initially in srbs glass - Volume of water - 1L o lookg -5'éc C = 840 water = jo'ngle? Tw=20°c TooL 3 kg- dausity of m0.500K = 0.5ookg Mass = Nolume x density [:IL : 103] Mass 10-3x 10² kg Mass water then melt accordin total ccording heat to melt taken by ice mg cat w ikg cii) when ice to caloriemetry Heat given by (water+ + glass) mcat + me & meat mil + micw (teg-o) = (malon+ mg Cw) ( 20 - teg} 0.100( 3.33 x 10+ 4200 teq) = (1442000 + 0.00 x 840) (0 toy 33300 + 420 teq (4200 +420)(20-tea) 33300 + 420 teq 84000 - 4620 teq 5040 teg teq = 10.059°c 50700 the heat 1 eiii) Person drinks all the water in glass, gained Q = mcat Q: (mwt mi) x 1 x 37 1.1 x 37 40. 7 Joules