11. A group of protons are traveling into a parallel plate capacitor charged to 190 V...
I need help on these problems!
10. You and your starship the USS are stationed at Earth, and have been ordered to the Wolf 359 system (7.9 light years from earth) to help with the clean up after the Borg attack. With your relativistic drive how fast do you need to go to reach the system in 2 years? Also, and more importantly, what is the name of your ship? 11. A group of protons are traveling into a parallel...
A parallel-plate capacitor is charged to 5000 V. A proton is
fired into the center of the capacitor at a speed of
3.9×105 m/s as shown in (Figure 1). The proton is
deflected while inside the capacitor, and the plates are long
enough that the proton will hit one of them before emerging from
the far side of the capacitor.
What is the impact speed of the proton?
Vo 0
A parallel-plate capacitor is charged to 5000 V. A proton is
fired into the center of the capacitor at a speed of
3.8×105 m/s as shown in (Figure 1). The proton is
deflected while inside the capacitor, and the plates are long
enough that the proton will hit one of them before emerging from
the far side of the capacitor.
What is the impact speed of the proton?
Express your answer with the appropriate units.
Vo
A beam of protons with various speeds is directed in the positive x direction. The beam enters a region with a uniform magnetic field of magnitude 0.49 T pointing into the page, as shown below. It is desired to use a uniform electric field (in addition to the magnetic field) to select from this beam only those protons with a speed of 1.23 105 m/s; that is, only these protons should be undeflected by the two fields. (a) Determine the electric...
I mostly just need to confirm my answers thanks!
In a typical parallel plate capacitor the separation distance between the plates is "d". For a charged capacitor, if you increase only the separation distance of the plates the following occurs: The potential (V) between the plates remains constant but the electric field increases, The potential (V) between the plates increases but the electric field remains constant. The potential (V) between the plates remains constant and the electric remains constant. The...
The drawing shows a parallel plate capacitor that is
moving with a speed of 35 m/s through a 4.2-T magnetic field. The
velocity v is perpendicular to the magnetic field. The
electric field within the capacitor has a value of 230 N/C, and
each plate has an area of 8.8 × 10 -4 m 2.
What is the magnitude of the magnetic force exerted on the positive
plate of the capacitor?
Chapter 21, Problem 09 The drawing shows a parallel...
A proton enters the top plate of a parallel capacitor via a small opening and accelerates towards the bottom plate. The proton’s entry speed is1.20×10^4 m/s. The separation of the plates is 10cm and the proton reaches the lower plate in 1.0 μs. What is the magnitude of the electric field in the capacitor?
A parallel-plate capacitor is charged to 5000. Volts. A proton is fired into the center of the capacitor at a speed of 3.0x105m/s. (Its initial velocity is parallel to both plates.) The proton is deflected while inside the capacitor and strikes one of the sides. What was the impact speed of the proton? (Neglect drag and gravity.)
A proton enters a parallel-plate capacitor traveling to the right at a speed of 1.276 x 10-5 m/s, as shown in the figure. The distance between the two plates is 1.62 cm. The proton enters the capacitor halfway between the top plate and the bottom plate; that is, a distance r = 0.810 cm from each plate, as shown in the figure. The capacitor has a 2.95 x 10* N/C uniform electric field between the plates that points downward from...
Capacitor A is a standard parallel-plate capacitor with
no dielectric. It was charged up (though is currently not attached
to anything) and currently has charge of Qo, a voltage
of Vo, a capacitance of Co, and a potential
energy of PEo. A dielectric with K = 67 is to be
inserted into capacitor A. Determine what the capacitance, charge,
voltage, & potential energy of capacitor A will be once the
dielectric is fully inserted.
I am just having difficulty understanding...