Question

Problem 10:  An object 1.7 cm high is held 3.1 cm from a person’s cornea, and its reflected image is measured to be 0.173 cm high.

Part (a) What is the magnification?
Numeric   : A numeric value is expected and not an expression.
m = __________________________________________


Part (b) What is the image distance in cm?
Numeric   : A numeric value is expected and not an expression.
d_i = __________________________________________


Part (c) Find the radius of curvature in cm of the convex mirror formed by the cornea.
Numeric   : A numeric value is expected and not an expression.
R = __________________________________________

Problem 12:  A myopic man has a far point of 110 cm.

Randomized Variables: d_o = 110 cm

What power contact lens in D (when on the eye) will correct his distant vision?
Numeric   : A numeric value is expected and not an expression.
P = __________________________________________

Answer 1

Bolto Hos el.7cm U =-3.1cm H = 0,173 cm Part (al magnification (m) ma 4 Ho m = 0.173 1.7 'm = 0.102 Part(b) As also know for m m= 는 Ve-mu distance -40.102x-3.1) com Hence, Image (V=01316cm Part II Using len's equation £ = // + b 3.1 X 0.316 f = uv V+u - 3.1 +0316 1 F = 0.352cm

R = 2 f R = 2x 0.352 R = 0.704 cm -0.704cm Hence, the readies of cowrature