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Consider the circuit shown in the figure below. (Let R1 = 4.00, R2 = 7.00, and E = 10.0 V.) 10.0 12 w R2 w 2.00 22 5.00 2 W R

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102 w 2.12 R2 w w $12 Ri a + R = 40, R2 = 75. & E= 10v The equivalence resistance first here lost & Share consecued in paraliSo carrent flowing I= Req > IE 10 4.883 I= 2.047 so voltage voltage is 22 resistor V 2.047 x 2 - V, 4.095 v For parate so com

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