the magnitude of total linear momentum of the system before
collision is 50 kg m/s. after the collision both carys stick and
move together. what js the magnitude of the final velocityHomework Answers
Add Answer to:
the magnitude of total linear momentum of the system before
collision is 50 kg m/s. after...
You have two carts labeled A and B as shown in the figure above. Cart A...
You have two carts labeled A and B as shown in the figure above. Cart A is twice the mass of cart B and is moving with a velocity of 5 m/s towards cart B. Cart Bis stationary. The magnitude of the total linear momentum of the system before the collision is 50 kg m/s. After the collision, both the carts stick and move together. What is the magnitude of the final velocity of the system? VA=5 m/s Vp=0 А...
14) (Conservation of linear momentum) An air cart of mass m=1 kg and speed vo-Im's moves...
14) (Conservation of linear momentum) An air cart of mass m=1 kg and speed vo-Im's moves toward second identical air cart that is at rest. When the carts collide, they stick together and move as one a) Using the conservation of linear momentum, calculate the velocity ve when the carts stick together (this is also the velocity of the center of mass after collision). b) Calculate the kinetic energy before and after collision. Is the collision elastic Without any calculation,...
An object has a kinetic energy of 296 J and a momentum of magnitude 21.3 kg-m/s....
An object has a kinetic energy of 296 J and a momentum of magnitude 21.3 kg-m/s. Find the speed and the mass of the object. speed m/s mass kg Three carts of masses m_1 = 5.00 kg, m_2 = 9.50 kg, and m_3 = 3.00 kg move on a frictionless, horizontal track with speeds of V_1 = 7.00 m/s to the right, v_2 = 3.00 m/s to the right, and v_3 = 3.50 m/s to the left, as shown below....
A 0.10 kg cart (cart 1) moves with a speed of 0.40 m/s on a frictionless...
A 0.10 kg cart (cart 1) moves with a speed of 0.40 m/s on a frictionless air track and collides with a stationary cart (cart 2) whose mass is 0.30 kg. The two carts stick together after the collision. put 0 m/s for the velocity of (cart 2) What is given? What is the formula for momentum? Is momentum conserved in this collision? Is kinetic energy conserved in this collision? What is the initial momentum of cart 1? What is...
Cart 1 Cart 2 Cart 1 Cart 2 no m/s LO After Collision Before Collision Two...
Cart 1 Cart 2 Cart 1 Cart 2 no m/s LO After Collision Before Collision Two lab carts have the same mass and are free to move on a horizontal track. The carts' wheels have negligible mass. Cart 1 travels to the right at 1.0 m/s and collides with cart 2, which is initially at rest, as shown at left above. Cart 2 has a compressed spring-loaded plunger with a non-negligible amount of stored energy. During the collision, the spring-loaded...
A 5.0-kg carl (cart 1) rolling cast on a level, frictionless track at 18.0 m/s, collides...
A 5.0-kg carl (cart 1) rolling cast on a level, frictionless track at 18.0 m/s, collides with a stationary 4.0-kg cart (cart 2). After the collision, cart 1 is still rolling cast, but now at a speed of 2.0 m/s. (a) Assuming the total momentum of the two-cart system is conserved, calculate the final velocity of the second cart. (b) Before the collision, the system's total kinetic energy was 810 J. Calculate the total kinetic energy of the two-cart system...
A cart of mass 0.20 kg starts moving at velocity 3.0 m/s collides inelastically with an...
A cart of mass 0.20 kg starts moving at velocity 3.0 m/s collides inelastically with an initially stationary cart of mass 0.40 kg. (A) If the carts stick together, what is their combined velocity immediately after the collision? (B) How much kinetic energy is lost in the collision?
Please answer #2 and #3 Question 2 Two carts with m 1 kg collide and then...
Please answer #2 and #3
Question 2 Two carts with m 1 kg collide and then stick together. The collision is completely inelastic. 2m 5 m/s a. What is the total impulse applied to the left cart? b. What is the total impulse applied to the right cart? c. What is the total impulse applied to the system of both carts? d. What is the change in the kinetic energy of the left cart? What is the change in the...
Two 2.0 kg bodies, A and B, collide. The velocities before the collision are (251101 m/s...
Two 2.0 kg bodies, A and B, collide. The velocities before the collision are (251101 m/s and i, - (-331+50))m/s. After the collision, VA= (-5.01 +40)m/s. What are(a) the final velocity of Band (b) the change in the total kinetic energy
1. Two asteroids collide head-on and stick together. Before the collision, asteroid A (mass 1,000 kg)...
1. Two asteroids collide head-on and stick together. Before the
collision, asteroid A (mass 1,000 kg) moved at 100 m/s and asteroid
B (mass 2,000 kg) moved at 80 m/s in the opposite direction. Use
momentum conservation (make a complete Momentum chart) to find the
velocity of the asteroids after the collision.
2. Two asteroids identical to those in (1) collide at right
angles and stick together. "Collide at right angles" means that
their initial velocities were perpendicular to each...
You have two carts labeled A and B as shown in the figure above. Cart A is twice the mass of cart B and is moving with a velocity of 5 m/s towards cart B. Cart Bis stationary. The magnitude of the total linear momentum of the system before the collision is 50 kg m/s. After the collision, both the carts stick and move together. What is the magnitude of the final velocity of the system? VA=5 m/s Vp=0 А...
14) (Conservation of linear momentum) An air cart of mass m=1 kg and speed vo-Im's moves toward second identical air cart that is at rest. When the carts collide, they stick together and move as one a) Using the conservation of linear momentum, calculate the velocity ve when the carts stick together (this is also the velocity of the center of mass after collision). b) Calculate the kinetic energy before and after collision. Is the collision elastic Without any calculation,...
An object has a kinetic energy of 296 J and a momentum of magnitude 21.3 kg-m/s. Find the speed and the mass of the object. speed m/s mass kg Three carts of masses m_1 = 5.00 kg, m_2 = 9.50 kg, and m_3 = 3.00 kg move on a frictionless, horizontal track with speeds of V_1 = 7.00 m/s to the right, v_2 = 3.00 m/s to the right, and v_3 = 3.50 m/s to the left, as shown below....
Cart 1 Cart 2 Cart 1 Cart 2 no m/s LO After Collision Before Collision Two lab carts have the same mass and are free to move on a horizontal track. The carts' wheels have negligible mass. Cart 1 travels to the right at 1.0 m/s and collides with cart 2, which is initially at rest, as shown at left above. Cart 2 has a compressed spring-loaded plunger with a non-negligible amount of stored energy. During the collision, the spring-loaded...
A 5.0-kg carl (cart 1) rolling cast on a level, frictionless track at 18.0 m/s, collides with a stationary 4.0-kg cart (cart 2). After the collision, cart 1 is still rolling cast, but now at a speed of 2.0 m/s. (a) Assuming the total momentum of the two-cart system is conserved, calculate the final velocity of the second cart. (b) Before the collision, the system's total kinetic energy was 810 J. Calculate the total kinetic energy of the two-cart system...
Please answer #2 and #3
Question 2 Two carts with m 1 kg collide and then stick together. The collision is completely inelastic. 2m 5 m/s a. What is the total impulse applied to the left cart? b. What is the total impulse applied to the right cart? c. What is the total impulse applied to the system of both carts? d. What is the change in the kinetic energy of the left cart? What is the change in the...
Two 2.0 kg bodies, A and B, collide. The velocities before the collision are (251101 m/s and i, - (-331+50))m/s. After the collision, VA= (-5.01 +40)m/s. What are(a) the final velocity of Band (b) the change in the total kinetic energy
1. Two asteroids collide head-on and stick together. Before the
collision, asteroid A (mass 1,000 kg) moved at 100 m/s and asteroid
B (mass 2,000 kg) moved at 80 m/s in the opposite direction. Use
momentum conservation (make a complete Momentum chart) to find the
velocity of the asteroids after the collision.
2. Two asteroids identical to those in (1) collide at right
angles and stick together. "Collide at right angles" means that
their initial velocities were perpendicular to each...
Most questions answered within 3 hours.
-
Rice Products in Bangladesh
Business behavior is derived in large part from the basic cultural
environment...
asked 31 minutes ago -
The following base sequence is found for a mRNA fragment from
wild-type E. coli: 5'- UAUCAGUAGAUAAUGUAACC-3'...
asked 54 minutes ago -
For this exercise, round all regression parameters to three
decimal places.
One of the two tables...
asked 1 hour ago -
What is the 5% level of significance for mean = 3.60, standard
deviation = 0.94, and...
asked 1 hour ago -
Prior to beginning work on this discussion, please read the
article by Hayley Peterson, 15 Companies...
asked 1 hour ago -
Which pair of aqueous solutions, when mixed, will form a
precipitate?
A) NaNO3 and AgC2H3O2
B)...
asked 2 hours ago -
1-Write an algorithm to get two numbers from the user (as
inputs) and calculate the sum...
asked 5 hours ago -
Define white-collar crime. What is the difference between
offender and offense-based definitions of white-collar crime? What...
asked 6 hours ago -
Consider a reaction which is 1st order with respect to A and 1st
order with respect...
asked 6 hours ago -
c++
The length of the hypotenuse of a right-angled triangle is the
square root of the...
asked 6 hours ago -
When a metal rod is heated, not only its resistance but also its
length and cross‐sectional...
asked 6 hours ago -
write a c++ program that computes the L^1 - Norm of a given
vector (L^1 norm...
asked 6 hours ago