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Part A What is the magnitude of the momentum of a 0.0073-kg marble whose speed is 0.70 m/s? Express your answer to two signif
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Answer #1

part a) momentum is denoted by P it should be equal to mass*velocity

given mass = 0.0073kg and v = 0.70m/s

P = 0.0073*0.70 = 5.11 * 10 -3 kg - m/s

part b) momentum is denoted by P

given m = 0.134 kg

P= 3.06 kg-m/s

we know P = m*v

m = mass

v = velocity

putting ,

3.06 = 0.134 * v

v = 22.8358 m/s

If any doubt then please comment humble request to you.

thanks...

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