Question

**Please Do Not Forget The Visual Representation. Thank You!!**

Problem Statement A 4.0-cm tall object is placed 50.0 cm from a diverging lens having a focal length of magnitude 25.0 cm. Draw the ray diagram for this situation. What is the location and height of the image? Is the image real or virtual? Visual Representation Draw an optical axis with the lens centered on the axis. Represent the object at the correct distance from the lens • Draw the three “special rays” from the top of the object • Extend the rays until they converge. • Draw the image.

Answer 1

given, ho = 4cm do 50cm f = -25cm + we know, - 1+1 do di det + > ! -95 +1 50 31 di (-35) (-50) ) di = 25-50 - di - 16.67cm. -ve value of image distance indieate that the image is located on the objects side of the lens. we know, magnification, M= hi ho do (-16-67) x 4 50 1-33 cm. positive value of heigne indicates the image hight is upright. The negative value of image distance indicates the existance 7 image located on the objects side Hence. It is virtual image, virtual of the lens, bject) B d som 50 cm. A B (object) A' B' (smage)