Atomic number of sulfur is 16.
When sulfur is in neutral state it contains 16 electrons.
So, electronic configuration of sulfur is -----------
In long form ------------------
1s2 2s2 2p6 3s2 3p4
In short form -------------
[Ne] 3s2 3p4
Answer ----------------
[Ne] 3s2 3p4
What is the abbreviated electron configuration for sulfur? O [Ne]3s23p4 O [Ne]3s13p3 O [Ne]3p6
Write out the abbreviated electron configuration of these elements: Arsenic Sulfur Sodium
43) The electron configuration of the sulfide ion (S2-) is A) [Ne]352 B) [Ne]3s23pl C) [Ne]3s23p4 D) [Ne]3p2 E) [Ne]3s23p6
Write an abbreviated electron configuration for each of the following sulfur Express your answer in condensed form, in order of increasing orbital energy. For example, [He]2s22p2 would be entered as [He]2s^22p^2.
A) write the abbreviated electron configuration for bismuth(Pb) B) write the abbreviated electron configuration for a iodide ion.
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 is the complete electron configuration for what element with a negative one charge?
The correct electron configuration for chlorine is 1s22s22p63s23p5 (abbreviated as [Ne]3s23p5). Assess the accuracy and logic of each of the statements below regarding chlorine and select the best choice. I. Every electron in the 3s and 3p shells of Cl feels about the same nuclear charge. II. There is space for only one more electron in the 3p orbitals of Cl. III. Therefore, electrons feel a high attraction to Cl so that Cl has a high electronegativity and electron affinity....
QUESTION 1 The following electron configuration belong to? O Copper O lodine O Zirconium QUESTION 2 The abbreviated form electron configuration for the element Caesium [Xej6s241145d Ne]3s2 Nel3s2 3p5 Ke6s QUESTION 3 The number of valence electrons for Bromine is QUESTION 4 The following electron configuration belongs to which group and period 1s22s22p83823p64823d104p9581 O group 5 period 5 O group 7 period 5 O group 1 period 5 group6 period 6
Which, if any, is the ground-state electron configuration for All St? O [Ne] or 1s22s22p6 O 1522s22p5 O 1522s22p6352 O [Ne] or 1s22s22p4 O None of the above
Complete this electron configuration for P [Ne]?
Give the EXPECTED abbreviated electron configuration for the ground state of the element shown below and the number of unpaired electrons expected to be in the highest energy subshell for. Enter your answer with subshells in increasing energy order, without superscripts and with spaces between subshells. Example: vanadium (V) = [Ar] 4s2 3d3 Abbreviated Electron Configuration Palladium (Pd): Answer Answer Unpaired Electrons Bismuth (Bi): Answer Answer Unpaired Electrons Germanium (Ge): Answer Answer Unpaired Electrons