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I need help with 11 and 12 please.

Data Table Mixture NaCl (s) + H2O (1) T (initial) T, (final) AT (T-T) -.20 25.00 24.80 NaNO, (s) + H2O (1) 24.99 24.11 -.88 N

NaNO3 is endothermic and dH is + sign NaCH3COO is exothermic and is - sign 9. Which solution(s) had little or no change in te

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11) Answer: NaCl (s) + H2O (1) NaCl (aq) AT = Tfinal - Tinitial = -0.20 °C The temperature decreases Heat absorbed by the sys

12) Answer: NaCl (s) + H2O (1) NaCl (aq) AT = Tfinal - Tinitial = -0.20 °C The temperature decreases Heat absorbed by the sys

Note: During dissolution entropy always increases. The change is entropy is always + ve.

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