Question

8. Which beaker contains more dissolved glucose particles? Solution A Solution B 50.0 mL of 1.25 M glucose solution. 50.0 mL of 25 % (m/m) glucose solution. Molar Mass Glucose - 180.156 g/mol Density of 25% solution = 1.56 g/mL

Answer 1

since we know that

no of moles is more that means particles is more

And

no of moles = molarity * volume in L

For solution A

amount of glucose = percent m/m *volume of solution * density /100

amount of glucose = 25*50.0*1.56 /100 = 19.5 g

moles of glucose = 19.5/180.156 = 0.10824 mol

For solution B

no of moles = 1.25 * 0.050 = 0.0625 mol

So solution A will have more particle than B