Red short-horned cattle are homozygous for the red allele, white cattle are homozygous for the white...
Red short-horned cattle are homozygous for the red allele, white cattle are homozygous for the white allele, and roan cattle are heterozygotes. Population A consists of 36% red, 16% white, and 48% roan cattle. What is the allele frequency of the red allele? (enter as decimal- zero point something)
Homework Answers
Here, the road cattle is heterozygous.
So Let, 'R' is the dominant allele responsible for the red cattle
and 'r' is the corresponding recessive allele responsible for the
white cattle.
Then, the following are the possible genotypes and corresponding
phenotypes -
RR = red cattle
Rr = roan cattle
rr = white cattle
Now, let 'p' be the frequency of the red allele(R) and 'q' be
the frequency of the white allele (r).
Also, 'p2' is the frequency of the homozygous red individuals
(RR)
'q2' is the frequency of the homozygous white individuals
(rr)
and '2pq' is the frequency of heterozygous individuals(Rr).
Here,
p2 (RR) = 36/100 = 0.36
q2 (rr) = 16/100 = 0.16
2pq (Rr) = 48/100 = 0.48
Now, we have to find the frequency of the red allele (R) i.e we
have to find the value of p.
p (R) = 0.36 + 0.48/2 = 0.36 + 0.24 = 0.60
Hence, the correct answer is 0.60 .
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