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Problem #4 VCE = 8 +0.7=6 8.7V Rsig RL=0 VA 150 + 10 (1+12 170 V ſo=100 15V o www 0.1 uF NCE Vi No & skr ਫੀਸਦ · e) End Avo Ri Ro Perid by fond R c) fund small signal small signal circuit. parameters

Answer 1

Given p=100 Given Vee 38.7 V VA = 1700 Nce = 8.7V Here Vi= Vcc VCE 15= Vcc R, & VEL ²3k2 Vo = Vo=15-8.7 No=67 volts: Vo =IE (3km) => 13 TE I= = 2:1 MA Bir B 100 -IE 2.1MA $+1 loot1 TL I=2.08 MA IB 2.08MA 100 IR = 20.8MA I =0o7+ 6-3 Vth = =oolt voi Vth = 7 volts 15 - R2 Vec .R2 RIER a Vich Rith R2 6.3 15 Ritry RitR₂ =₂ fois

General Design Rules, Generally tu bias in stable LORth < (3+1). RE R,R ~ (loot! 13 km) RAR 10x Rif = 30.3 RIR = 30-3 (R+R2) Retry 2,4=363 (842 43 ) R1 = 72.144 kn Rith = ₂ ( 15 ) 12:14 +R2 = R2115 Ry = 52: 24 km

small sig © signal parameters 2:08 MA = 0.08 Alv Y 26 mv fm = I Xx = ß = 1.25 KM 0.0% gm Vo= VA 170 =81.73 km 2:08MA IL d) IE Rille, "gmV &ro= 81.75k galvi gny- t I 33k2 l N

es Rout= Il a So IIRE 3+1 125 81.73113k.ll 1004) => Rout = 12-321 ki z Ya+(+1)(ell ro) 1·25+(* [ 3 || 8173) Ri= 243.526 (Bt{ Avo rollre Yntni) (rolle) Av. = 0.995 Vv =