For the venturi shown, deflection of the mercury in the differential gage is .36. Find Q....
A Venturi meter equipped with a differential pressure gage is used to measure the flow rate of water at 15°C (p = 999.1 kg/m”) through a 5-cm- diameter horizontal pipe. The diameter of the Venturi neck is 3 cm, and the measured pressure drop is 5.1 kPa. Taking the discharge coefficient to be 0.98, determine the volume flow rate of water and the average velocity through the pipe. 5 cm 3 cm Differential pressure gage Is The volume flow rate...
Kerosene with a specific gravity of 0.823 is flowing downward through the venturi meter shown in Figure 4 a) 100 mm inside diameter 50 mm inside diameter Mercury (SG 13.6) Figure 4: Venturi meter ) By using the Bemoulli and the continuity equations, show that the manometer deflection, h, in the Figure 4 is given by 15吸 31.05g (8 Marks) manometer deflection h is 700 mm, compute the volume flow rate of the
A fluid manometer is open to the atmosphere as shown in figurel. If the gage pressure of the pressurized air is 0.07MPa, find the differential height h3 if hl=60cm and h2= 45cm. Mercury SG: 13.6 Ar! Methane S6= 0.47 Gasoline 56. 0.70 Figure I
7 . Determine the differential height h of the mercury column if the gage pressure of the air in the tank shown in is measured to be 80 kPa (Non-anonymous question ) (6 Points) 80 Kpa -Oil SG =.81 60 cm Air -Water 30 cm -Mercury SG -14
A vertical Venturi meter equipped with a differential U-tube manometer as shown in Figure , is used to measure the flow rate of liquid propane at 10°C (p = 514.7 kg/m3) flowing through a 'd1' mm diameter vertical pipe. For a discharge coefficient of 'cd', determine the actual volume flow rate of propane through the pipe with the given data. Pipe dia., d1 = Throat dia., d2 = Vertical dist., Y1 = Vertical dist., Y2 = Disch. Coeff., Cd =...
1. (30%) in the Venturi pipe shown, gage A indicates a pressure of 130 KPA. The diameter of the normal pipe is D -0.5 m and the discharge is Q-0.15 m/s. Assume atmospheric pressure 100 kPa, vapor pressure 2.34 kPa. and y- 9.81 kN/m Pipe Throat 1.1 The velocity head in the pipe at section A is: A) 0.044 m B) 0.815 m 1.2 The pressure head in the pipe at section A is: C) 0.030 m D) 0.0815 m...
Find the velocity of the flow of an oil through pipe when the difference of mercury level in a differential U - tube manometer connected to the two tapping of the pitot tube is 100 mm. The coefficient of the pitot tube = 0.98, the specific gravity of oil and mercury are 0.8 and 13.6 respectively. Density of water 1000 kg/m3 Select one: O a. 5.62 m/s O b.5.49 m/s O c.5.22 m/s O d. 4.88 m/s O e. 4.98...
Y = 3 m
(pa-pb) = 46 KN/m^2
Q.2. Figure:2 shows a U tube differential manometer connecting two pressure pipes at A and B. The pipe A and B contains water and manometer fluid is mercury. If the pressure difference between two pipe (p.-p.) is (X) kN/m’. Calculate the difference in level (h). (3 Marks) Water water 0.3 m у h Mercury Sp. gravity 13.6
Problem 3: For the beam shown find the slope and deflection at point B and C 100 KN 300 kN-m 6 m E = constant = 70 GPa 1 = 500 (106) mm Problem 4: For the beam shown find the deflection at point B and the slope at point A 80 KN 12 m 12 m E = constant = 200 GPa I = 600 (106) mm
Q.6 (a) Find the general solution to the Partial Differential Equation: (D2 + 4DD' - 5D2)z = sin(x + 2y) +ex-2y