Question

Find the velocity of the flow of an oil through pipe when the difference of mercury level in a differential U - tube manometer connected to the two tapping of the pitot tube is 100 mm. The coefficient of the pitot tube = 0.98, the specific gravity of oil and mercury are 0.8 and 13.6 respectively. Density of water 1000 kg/m3 Select one: O a. 5.62 m/s O b.5.49 m/s O c.5.22 m/s O d. 4.88 m/s O e. 4.98 m/s

Answer 1

^{Sol:- option- (b) Given! Mano meter reading (zm) - too mm coitmm of oila 0.8 = 5t specific gravity of mercury = 13,625m specific gravity coefficient of sikot tube (c) = 0.98 Density of water (J 1000 kg/m3 oil - Sex Sw sensity of 50.8 X 1000 = 800 kg/m3 Density of Mercury, sm x Bw = 13.6 X 1000 = 13600 regim 3 Approach и с 29 (sm-St) 2m Se 249.81 (13600 - 800) xol u=0.48 800 -0.98*5.60 = 5.49 mis Please upvote feedback and give}

Answer 2

Answer to the same problem available in.  Revised Ninth edition of Fluid Mechanics and Hydraulic Machines by R.K.Bansal. You can find it in Chapter6 as an example problem under Pitot Tube topic.