Question

Figure 1 R1 = 12 12 R2 = 62 R3 = 24 82 P3 = 96 watts Rs = 102 R4 = 82
Question 1 1 pts Questions 1 through 10 pertain to figure 1 How much voltage is being dropped by resistor #1? 0 24v 12v 48V 1
Question 2 1 pts Questions 1 through 10 pertain to figure 1 How much power is being dissipated by resistor #1? 48 watts 24 wa
Question 3 1 pts Questions 1 through 10 pertain to figure 1 How much voltage is being dropped by resistor #2? 24v 12v 48v 16v
Question 4 1 pts Questions 1 through 10 pertain to figure 1 How much power is being dissipated by resistor #2? 48w 24w 32w 40
Question 5 1 pts Questions 1 through 10 pertain to figure 1 How much voltage is being dropped by resistor #4? 24v 12v 48V 16v
Question 6 1 pts Questions 1 through 10 pertain to figure 1 How much power is being dissipated by resistor #4? 48w 24w 32w 40
Question 7 1 pts Questions 1 through 10 pertain to figure 1 How much voltage is being dropped by resistor #5? 24v 12v 48v 20v
Question 8 1 pts Questions 1 through 10 pertain to figure 1 What is the total power being dissipated in this circut? 120w 180
Question 9 1 pts Questions 1 through 10 pertain to figure 1 What is the source voltage in this circuit? 60v 80V 100v 120v
Question 10 1 pts Questions 1 through 10 pertain to figure 1 What is the total amount of current in this circuit? ФОА 1A 2A О
0 0
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Answer #1

Ri Ra=60t ww -122 mine + Ví tva + It R3E =2H2 P2=966 ANT + - Vst um Ry=8 R5=104 relations 0 we have power P= I²R P3= I R in g2 Pole 408 R 3 P= I & R = 4(12)=48 W P = 48 watts © across R2 Va= Ip R2 = 2(6)=12 W la power across R2 P2= I2 R2 = 4(6)=24 waTotal power Pol+b+y+678 p= 487 24+96+32+ 40 P = 240 watt Source Voltage ♡ = V, +V₂ + V +V4 +45 V: 24+1% +16+-&01 13 V=240, V2

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