Question

Figure 5 Ri= 202 120 volts R2= 20 2 Ry = 2012

Answer 1

Soln)

Ri=20r Bub VA A Iz R₂ 200 Iz R3=202 120 Assume uc=0 V - YA = 120 > 1A=-120 V Applying Kel at Node 'B' - Il Iz t Iz [ка. KLL-> sum af incoming current in a node is equal to sum of outgoing current from the node de] R · Ij = Vn – Vo [one's Low] Ij = verven en in 1 270] R2 . I 11 Ugue UB R3 putting the value of I, , Iz 4 Iz on erano . UB RI UB R R₃ => VA-VB VB TVB 20 20 = > 3 UB VA 3 VB- -40V -120 3 UB=-you 23) I = VA-VB R -120-(-40) 20 ЧА Total resistance of ciruit = Sounce voltage Sounce current - 120 VA-ve 지 4 Total resistance = 3or Ary 24) source current is the total current from the circuit IL = sowice current = -4A Here, -ve sign only implies that the direction of current is opposite to our assumed direction. | Total current = 4A Ary 257 Total power = (source voltage)(source Current) :14)(120) - Total Power = 480 W Aug 26) Iz = UB 40 - -2 R₂ 20 current through R₂ = 2A Ary. 27) Power through R2 = (UB-Ve) Iz Power though R₂ = (-40) (-2) = 80w JAU 28) Voltage drop across R3 = (U8-V) - - 40 v -ve sign only implies the direction. oy voltage crop across R₂ = 400 29) power acrom R2 = (g-vejs R3 (40) = 80W 20 Power acron R3 = 80w Any