Tiger Woods hits a golf ball with an initial speed of 48 ft/sec. The height h...

Question

Question

math algebra

Answer 1

Answer #1

Guven f(t) = -16(t)²+48t

At time t = 1 second

Height of ball, f(1) = -16(1)²+48(1)

= -16+48 = 32

Therefore, height of ball after one second = 32 feet

Golf ball hits the ground $\Rightarrow$ f(t) = 0

f(t) = -16(t)²+48t = 0

-16t (t -3) = 0

$\Rightarrow$ -16t = 0 , (t-3) = 0

t=0, t=3

I.e., at t = 0 seconds, initially ball is on ground

And t = 3 seconds after hitting the ball, ball reaches ground.

The answers are,

(i) 32 feet

(ii) 3 seconds

Answer 2

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