Question

AC generators (often called alternators) used in airplanes and submarines are quite common having a frequency of 400 HZ and an output voltage of 24 volts (rms). If one of these generators is connected to a diode bridge rectifier with a 4000-μF capacitor.

(a) Calculate the load current when a resistive load of 2.4 Ω is connected.

(b) Calculate the AC ripple voltage across the above load.

(c) Calculate the average current passing through the diodes.

(d) Calculate the minimum value of a capacitor should be used if the ripple voltage needs to be less than 1.0 Vpp.

Answer 1

Q КРІ 123 AC c R=2.42 2 Genonton 24V цоон 4. D2 A Dy During will be for world the hall cycle Diode Di & D2 biased and during -ve half cycle diode Dz & Du get will be for world biased, is for full bridge rectition, the output Voltage given as, 2x 52x24 21.5 2106075 Volts. Vo = it T Load currend + IOS zolo 9.00316 Amp. Vin 个 Vont TI 21 34 Un اوما - K T 27 37 ->wt

Io sto Load current wave form. -K et 37 4T Vo wt output voltage with filter Capacitance 27 37 .اما ہ 4T (6) AC gripple voltage vo (vr 2 fC RL 41 21. 60 75 2x 400 x 4000x 10 106 x 2.4 Vy = 2. 8135 Volls, the minimum d) to maintain the ripple voltage of 10 Value of a Capacitor should be Vr vo 2nf.C-RL Vo Cminimum= 2.f. RL Vr 2 Vm Give Nr here is App =\V =) Upp- Vom Va sms 2. Vm= Upp UPP yms 282 22 2

Vo (minimum 2. f. Re ( 252 21.6075 x 252 11 2x 400 x 2.4 (minimuna 31.830 ME the diodes (C) Average current passing through (512) Io (2D) ang Io 2 9600316 2 ? (ID)ang = 450158 Amps.