A manager is in a tizzy and asks if you can construct an Individuals/Moving Range control chart for the data he provided, treating each data point as an independent measurement taken sequentially.
In addition, he wants an estimate of process capability for a specification of 74.000 ± 0.015 using this set of charts.
Homework Answers
The control limits are:
| Sample size | 5 | |
| Number of samples | 20 | |
| Mean | Range | |
| Upper Control Limit, UCL | 74.01401 | 0.04725 |
| Center | 74.00111 | 0.02235 |
| Lower Control Limit, LCL | 73.98821 | 0.00000 |
The control charts are:
The process is in statistical control.
Process capability index = minimum((74.00111- 73.98821)/(3*0.001006) , (74.01401 - 74.0011)/(3*0.001006)) = 4.274
| 74.03 | 74.002 | 74.019 | 73.992 | 74.008 |
| 73.995 | 73.992 | 74.001 | 74.011 | 74.004 |
| 73.988 | 74.024 | 74.021 | 74.005 | 74.002 |
| 74.002 | 73.996 | 73.993 | 74.015 | 74.009 |
| 73.992 | 74.007 | 74.015 | 73.989 | 74.014 |
| 74.009 | 73.994 | 73.997 | 73.985 | 73.993 |
| 73.995 | 74.006 | 73.994 | 74 | 74.005 |
| 73.985 | 74.003 | 73.993 | 74.015 | 73.988 |
| 74.008 | 73.995 | 74.009 | 74.005 | 74.004 |
| 73.998 | 74 | 73.99 | 74.007 | 73.995 |
| 73.994 | 73.998 | 73.994 | 73.995 | 73.99 |
| 74.004 | 74 | 74.007 | 74 | 73.996 |
| 73.983 | 74.002 | 73.998 | 73.997 | 74.012 |
| 74.006 | 73.967 | 73.994 | 74 | 73.984 |
| 74.012 | 74.014 | 73.998 | 73.999 | 74.007 |
| 74 | 73.984 | 74.005 | 73.998 | 73.996 |
| 73.994 | 74.012 | 73.986 | 74.005 | 74.007 |
| 74.006 | 74.01 | 74.018 | 74.003 | 74 |
| 73.984 | 74.002 | 74.003 | 74.005 | 73.997 |
| 74 | 74.01 | 74.013 | 74.02 | 74.003 |
Add Answer to:
A manager is in a tizzy and asks if you can construct an
Individuals/Moving Range control...
Construct an Xbar / S control chart and determine the process capability index of it for...
Construct an Xbar / S control chart and determine the process
capability index of it for a specification of 74.000 ± 0.015.
Rock Dept. Data Inside Diameter Measurements (mm) for Automobile Engine Piston Rings Sample Number 4 S 7 10 74.030 73.995 73.988 74.002 73.992 74.009 73.995 73.985 74.008 73.998 73.994 74.004 73.983 74.006 74.012 74.000 73.994 74.000 73.984 74.000 73.982 74.004 74.010 74.015 73.982 13 Observations 74.019 73.992 74.001 74.011 74.021 74.005 73.993 74.015 74.015 73.989 73.997 73.985 73.994...
How to determine the process capability index of an Xbar/s, Xbar/R and I/MR chart for a...
How to determine the process capability index of an Xbar/s, Xbar/R and I/MR chart for a specification of 74.000 ± 0.015? Sample Number Set 1 Set 2 Set 3 Set 4 Set 5 Xi Si 1 74.030 74.002 74.019 73.992 74.008 74.010 0.0148 2 73.995 73.992 74.001 74.011 74.004 74.001 0.0075 3 73.988 74.024 74.021 74.005 74.002 74.008 0.0147 4 74.002 73.996 73.993 74.015 74.009 74.003 0.0091 5 73.992 74.007 74.015 73.989 74.014 74.003 0.0122 6 74.009 73.994 73.997 73.985...
exchange rates = {'0.0045': 3, '0.0160': 2, '-0.0028': 6, '-0.0157': 1, '-0.0443': 1, '-0.0232': 1, '-0.0065':...
exchange rates = {'0.0045': 3, '0.0160': 2, '-0.0028': 6, '-0.0157': 1, '-0.0443': 1, '-0.0232': 1, '-0.0065': 9, '-0.0080': 12, '0.0052': 1, '-0.0052': 3, '-0.0283': 1, '-0.0087': 1, '-0.0020': 9, '-0.0290': 2, '0.0180': 3, '0.0030': 15, '-0.0170': 2, '0.0000': 63, '-0.0185': 3, '-0.0055': 5, '0.0148': 1, '-0.0053': 1, '0.0265': 1, '0.0010': 22, '-0.0015': 5, '0.0137': 1, '-0.0137': 2, '-0.0023': 2, '0.0008': 10, '0.0055': 6, '-0.0025': 6, '-0.0125': 2, '0.0040': 14, '0.0260': 1, '0.0070': 8, '0.0210': 1, '-0.0070': 8, '0.0395': 1, '-0.0040':...
(20) TRUE or FALSE: Correlation is a dimensionless quantity with the strict range 0 SPs. 0.00...
(20) TRUE or FALSE: Correlation is a dimensionless quantity with the strict range 0 SPs. 0.00 0.01 0.02 0.03 0.04 0,05 0.06 0.07 0.08 0.09 -0.0 0.500) 0.490) 0.4920 04880- 0.4840-0.4801-0.4761-0.472-0.4681-0.4641- -0.1 0.4602 0.4562 0.4522 0.4483 0.4443 0.4404 0.4364 0.4325 0.4286 0.4247 -0.2 0.4207 0.4168 0.4129 0.4090 0.4052 0.4013 0.3974 0.3936 0.3897 0.3859 -0.3 0.3821 0.3783 0.3745 0.3707 0.3669 0.3632 0.3594 0.3557 0.3520 0.3483 -0.4 0.3446 0.3409 0.3372 0.3336 0.3300 0.3264 0.3228 0.3192 0.3156 0.3121 -0.5 0.3085 0.3050 0.3015 0.2981...
VI HW Score: 23.53%, 4 of 17 pts 25.3.9 Question Help se the standard normal table...
VI HW Score: 23.53%, 4 of 17 pts 25.3.9 Question Help se the standard normal table to find the 2-score that corresponds to the given percentile. If the area is not in the table, use the entry closest to the area. If the area is hallway between two entries, use the score halay between the corresponding 2-cores. If convenient, use technology to find the score P20 Click to view page 1 of the title Click to view. 2 of the...
Consider the hypothesis statement shown below using a = 0.10 and the data to the right...
Consider the hypothesis statement shown below using a = 0.10 and the data to the right from two independent samples. HO: H1 - H220 H1: 1-12 0 a) Calculate the appropriate test statistic and interpret the result. b) Calculate the p-value and interpret the result. Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table. X = 114 X2 = 127 6 = 36 02 = 40 n...
how to solve B? 6.2.1 Question Help Given a standardized normal distribution (with a mean of...
how
to solve B?
6.2.1 Question Help Given a standardized normal distribution (with a mean of O and a standard deviation of 1), complete parts (a) through (d) EI! Click here to view page 1 of the cumulative standardized normal distribution table. Click here to view page 2 of the cumulative standardized normal distribution table. G. WE WC PM WIB The probability that is less than 1.53 is 0.9370 (Round to four decimal places as needed) b. What is the...
Suppose a random sample of size 15 is taken from a normal population with mean 25...
Suppose a random sample of size 15 is taken from a normal population with mean 25 and standard deviation 5; and a second, independent random sample of size 21 is taken from a normal population with mean 10 and standard deviation 4. Find the probability P(X- X2 2 17). (Use Appendix Table 3. Give your answer to four decimal places.) p(7. - 12 2 17) = 1.282 Incorrect Table In Standard Normal Distribution Cumulative Probabilities Let 2 be a standard...
z .09 .08 .07 .06 .05 .04 .03 .02 .01 .00 z -3.4 0.0002 0.0003 0.0003 ...
z .09 .08 .07
.06 .05 .04 .03
.02 .01 .00 z
-3.4 0.0002 0.0003
0.0003 0.0003 0.0003
0.0003 0.0003 0.0003
0.0003 0.0003 -3.4
-3.3 0.0003 0.0004
0.0004 0.0004 0.0004
0.0004 0.0004 0.0005
0.0005 0.0005 -3.3
-3.2 0.0005 0.0005
0.0005 0.0006 0.0006
0.0006 0.0006 0.0006
0.0007 0.0007 -3.2
-3.1 0.0007 0.0007
0.0008 0.0008 0.0008
0.0008 0.0009 0.0009
0.0009 0.0010 -3.1
-3.0 0.0010 0.0010
0.0011 0.0011 0.0011
0.0012 0.0012 0.0013
0.0013 0.0013 -3.0
-2.9 0.0014 0.0014
0.0015 0.0015 0.0016
0.0016 0.0017 ...
these two questions im having trouble on. Provides the tables for both M 6.2.75 се Use...
these two questions im having trouble on. Provides the tables
for both
M 6.2.75 се Use a standard normal distribution table to obtain the Z-score that has an area of 0.975 to its right. Click here to view page 1 of the normal distribution table, As Click here to view page 2 of the normal distribution table. Za St (Round to two decimal places as needed.) normal distribution page 1 Areas under the standard normal curve Second decimal place in...
Construct an Xbar / S control chart and determine the process
capability index of it for a specification of 74.000 ± 0.015.
Rock Dept. Data Inside Diameter Measurements (mm) for Automobile Engine Piston Rings Sample Number 4 S 7 10 74.030 73.995 73.988 74.002 73.992 74.009 73.995 73.985 74.008 73.998 73.994 74.004 73.983 74.006 74.012 74.000 73.994 74.000 73.984 74.000 73.982 74.004 74.010 74.015 73.982 13 Observations 74.019 73.992 74.001 74.011 74.021 74.005 73.993 74.015 74.015 73.989 73.997 73.985 73.994...
(20) TRUE or FALSE: Correlation is a dimensionless quantity with the strict range 0 SPs. 0.00 0.01 0.02 0.03 0.04 0,05 0.06 0.07 0.08 0.09 -0.0 0.500) 0.490) 0.4920 04880- 0.4840-0.4801-0.4761-0.472-0.4681-0.4641- -0.1 0.4602 0.4562 0.4522 0.4483 0.4443 0.4404 0.4364 0.4325 0.4286 0.4247 -0.2 0.4207 0.4168 0.4129 0.4090 0.4052 0.4013 0.3974 0.3936 0.3897 0.3859 -0.3 0.3821 0.3783 0.3745 0.3707 0.3669 0.3632 0.3594 0.3557 0.3520 0.3483 -0.4 0.3446 0.3409 0.3372 0.3336 0.3300 0.3264 0.3228 0.3192 0.3156 0.3121 -0.5 0.3085 0.3050 0.3015 0.2981...
VI HW Score: 23.53%, 4 of 17 pts 25.3.9 Question Help se the standard normal table to find the 2-score that corresponds to the given percentile. If the area is not in the table, use the entry closest to the area. If the area is hallway between two entries, use the score halay between the corresponding 2-cores. If convenient, use technology to find the score P20 Click to view page 1 of the title Click to view. 2 of the...
Consider the hypothesis statement shown below using a = 0.10 and the data to the right from two independent samples. HO: H1 - H220 H1: 1-12 0 a) Calculate the appropriate test statistic and interpret the result. b) Calculate the p-value and interpret the result. Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table. X = 114 X2 = 127 6 = 36 02 = 40 n...
how
to solve B?
6.2.1 Question Help Given a standardized normal distribution (with a mean of O and a standard deviation of 1), complete parts (a) through (d) EI! Click here to view page 1 of the cumulative standardized normal distribution table. Click here to view page 2 of the cumulative standardized normal distribution table. G. WE WC PM WIB The probability that is less than 1.53 is 0.9370 (Round to four decimal places as needed) b. What is the...
Suppose a random sample of size 15 is taken from a normal population with mean 25 and standard deviation 5; and a second, independent random sample of size 21 is taken from a normal population with mean 10 and standard deviation 4. Find the probability P(X- X2 2 17). (Use Appendix Table 3. Give your answer to four decimal places.) p(7. - 12 2 17) = 1.282 Incorrect Table In Standard Normal Distribution Cumulative Probabilities Let 2 be a standard...
z .09 .08 .07
.06 .05 .04 .03
.02 .01 .00 z
-3.4 0.0002 0.0003
0.0003 0.0003 0.0003
0.0003 0.0003 0.0003
0.0003 0.0003 -3.4
-3.3 0.0003 0.0004
0.0004 0.0004 0.0004
0.0004 0.0004 0.0005
0.0005 0.0005 -3.3
-3.2 0.0005 0.0005
0.0005 0.0006 0.0006
0.0006 0.0006 0.0006
0.0007 0.0007 -3.2
-3.1 0.0007 0.0007
0.0008 0.0008 0.0008
0.0008 0.0009 0.0009
0.0009 0.0010 -3.1
-3.0 0.0010 0.0010
0.0011 0.0011 0.0011
0.0012 0.0012 0.0013
0.0013 0.0013 -3.0
-2.9 0.0014 0.0014
0.0015 0.0015 0.0016
0.0016 0.0017 ...
these two questions im having trouble on. Provides the tables
for both
M 6.2.75 се Use a standard normal distribution table to obtain the Z-score that has an area of 0.975 to its right. Click here to view page 1 of the normal distribution table, As Click here to view page 2 of the normal distribution table. Za St (Round to two decimal places as needed.) normal distribution page 1 Areas under the standard normal curve Second decimal place in...
Most questions answered within 3 hours.
-
Industry: Telecommunications in India
Here, you need to discuss the sources of the growth pattern
and...
asked 38 minutes ago -
Hydrobromic acid
dissolves solid iron according to the followiaung reaction:
Fe(s)+2HBr(aq)→
FeBr2(aq)+ H2(g)
Part A. What...
asked 2 hours ago -
Verify the following vector identity in SPHERICAL
COORDINATES.
div(curl(A)) = 0
asked 3 hours ago -
The work function (Φ) for a metal is 7.50×10-19 J.
What is the longest wavelength (nm)...
asked 4 hours ago -
1. Would the following procedural changes cause the
calculated mass percent Ni2+ ion in Ni(NH3)nCl2 to...
asked 6 hours ago -
1. Why does the voltage of the capacitor vary with frequency?
where does this missing voltage...
asked 7 hours ago -
p p please write each step out clearly
3. A manager of a company is considering...
asked 6 hours ago -
On October 1, Ebony Ernst organized Ernst Consulting; on October
3, the owner contributed $83,540 in...
asked 7 hours ago -
A.)As an electron moves through a region of space, its speed
decreases from 9.60 × 106...
asked 7 hours ago -
In java with the netbeans program do:
Through object programming
Create a class "ContadorP", which is...
asked 7 hours ago -
Pattern Corporation acquired all of Science
Company's outstanding stock on January 1, 2016 for $600,000 cash....
asked 7 hours ago -
Here are all accounts Tyler Co. maintains.
Tax expenses $4,750
Common stocks $48,840
SG&A expenses $2,500...
asked 8 hours ago