How to determine the process capability index of an Xbar/s, Xbar/R and I/MR chart for a specification of 74.000 ± 0.015?
Sample Number | Set 1 | Set 2 | Set 3 | Set 4 | Set 5 | Xi | Si |
1 | 74.030 | 74.002 | 74.019 | 73.992 | 74.008 | 74.010 | 0.0148 |
2 | 73.995 | 73.992 | 74.001 | 74.011 | 74.004 | 74.001 | 0.0075 |
3 | 73.988 | 74.024 | 74.021 | 74.005 | 74.002 | 74.008 | 0.0147 |
4 | 74.002 | 73.996 | 73.993 | 74.015 | 74.009 | 74.003 | 0.0091 |
5 | 73.992 | 74.007 | 74.015 | 73.989 | 74.014 | 74.003 | 0.0122 |
6 | 74.009 | 73.994 | 73.997 | 73.985 | 73.993 | 73.996 | 0.0087 |
7 | 73.995 | 74.006 | 73.994 | 74.000 | 74.005 | 74.000 | 0.0055 |
8 | 73.985 | 74.003 | 73.993 | 74.015 | 73.988 | 73.997 | 0.0123 |
9 | 74.008 | 73.995 | 74.009 | 74.005 | 74.004 | 74.004 | 0.0055 |
10 | 73.998 | 74.000 | 73.990 | 74.007 | 73.995 | 73.998 | 0.0063 |
11 | 73.994 | 73.998 | 73.994 | 73.995 | 73.990 | 73.994 | 0.0029 |
12 | 74.004 | 74.000 | 74.007 | 74.000 | 73.996 | 74.001 | 0.0042 |
13 | 73.983 | 74.002 | 73.998 | 73.997 | 74.012 | 73.998 | 0.0105 |
14 | 74.006 | 73.967 | 73.994 | 74.000 | 73.984 | 73.990 | 0.0153 |
15 | 74.012 | 74.014 | 73.998 | 73.999 | 74.007 | 74.006 | 0.0073 |
16 | 74.000 | 73.984 | 74.005 | 73.998 | 73.996 | 73.997 | 0.0078 |
17 | 73.994 | 74.012 | 73.986 | 74.005 | 74.007 | 74.001 | 0.0106 |
18 | 74.006 | 74.010 | 74.018 | 74.003 | 74.000 | 74.007 | 0.0070 |
19 | 73.984 | 74.002 | 74.003 | 74.005 | 73.997 | 73.998 | 0.0085 |
20 | 74.000 | 74.010 | 74.013 | 74.020 | 74.003 | 74.009 | 0.0080 |
How to determine the process capability index of an Xbar/s, Xbar/R and I/MR chart for a...
Construct an Xbar / S control chart and determine the process
capability index of it for a specification of 74.000 ± 0.015.
Rock Dept. Data Inside Diameter Measurements (mm) for Automobile Engine Piston Rings Sample Number 4 S 7 10 74.030 73.995 73.988 74.002 73.992 74.009 73.995 73.985 74.008 73.998 73.994 74.004 73.983 74.006 74.012 74.000 73.994 74.000 73.984 74.000 73.982 74.004 74.010 74.015 73.982 13 Observations 74.019 73.992 74.001 74.011 74.021 74.005 73.993 74.015 74.015 73.989 73.997 73.985 73.994...
A manager is in a tizzy and asks if you can construct an
Individuals/Moving Range control chart for the data he provided,
treating each data point as an independent measurement taken
sequentially.
In addition, he wants an estimate of process capability for a
specification of 74.000 ± 0.015 using this set of charts.
Table 5-3 Inside Diameter Measurements (mm) for Automobile Engine Piston Rings Sample Number Observations 2 3 4 5 6 7 8 9 10 11 12 13 74.030...
exchange rates = {'0.0045': 3, '0.0160': 2, '-0.0028': 6, '-0.0157': 1, '-0.0443': 1, '-0.0232': 1, '-0.0065': 9, '-0.0080': 12, '0.0052': 1, '-0.0052': 3, '-0.0283': 1, '-0.0087': 1, '-0.0020': 9, '-0.0290': 2, '0.0180': 3, '0.0030': 15, '-0.0170': 2, '0.0000': 63, '-0.0185': 3, '-0.0055': 5, '0.0148': 1, '-0.0053': 1, '0.0265': 1, '0.0010': 22, '-0.0015': 5, '0.0137': 1, '-0.0137': 2, '-0.0023': 2, '0.0008': 10, '0.0055': 6, '-0.0025': 6, '-0.0125': 2, '0.0040': 14, '0.0260': 1, '0.0070': 8, '0.0210': 1, '-0.0070': 8, '0.0395': 1, '-0.0040':...
how
to solve B?
6.2.1 Question Help Given a standardized normal distribution (with a mean of O and a standard deviation of 1), complete parts (a) through (d) EI! Click here to view page 1 of the cumulative standardized normal distribution table. Click here to view page 2 of the cumulative standardized normal distribution table. G. WE WC PM WIB The probability that is less than 1.53 is 0.9370 (Round to four decimal places as needed) b. What is the...
please help me with this calculations. i used the data analysis
to figure out the correlation matrix.
Below there are 10 Assets
row 66: Mean Return
Row 67: Standard Deviation
Row 69: Annual Return
Row 70 Annual ST. deviation
I used the data analysis to calculate the CORRELATION matrix
with the DATA ASSET RANGE. now im stuck on how to calculate the
covariance matrix
Enr gy Telc 0.0559 0.0508 0.0093 0.0297 0.0352 0.0065 0.0249 0.0646 0.0165 0.0554 0.0524 0.0278 0.0307...
Determine the area under the standard normal curve that lies to
the right of a(Z) = -0.42, b(Z) =0.54, c(Z) = - 0.76, and d(Z) =
-1.91
MyStatLab Data Set - Google Chrome statcrunch.com/app/?dlim=comma&ft=false&dataurl=https%3a%2f%2fxlitemprod.pearsoncmg.com%2fGetPlayerFile.ashx%3fguid%3d1e9f4376-4819-4d55-8ca0-c41ee702bb63 MyStatLab Data Set StatCrunch Applets Edit Data | StatGraph | Help Row vari vari var2 var12 var13 var14 ve -3.4 -3.3 -3.2 -2.9 -2.8 -2.7 -2.6 -2.5 -2.4 -2.3 HNMONOFHHHHHNNNNNNNNNN -2.2 -2.1 -2 -1.9 0.0003 0.0005 0.0007 0.001 0.0013 0.0019 0.0026 0.0035 0.0047 0.0062 0.0082 0.0107...
HOMEWOIK. Modules mulleWUIR (LI. Score: 0 of 1 pt 7.2.15 Find the Z-score such that the area under the standard normal curve to the right is 0.37 =) Click the icon to view a table of areas under the normal curve. The approximate Z-score that corresponds to a right tail area of 0 37 is (Round to two decimal places as needed.) Enter your answer in the answer box and then click Check Answer Amon MG 1544 (1).jpg stats 10.jpg...
pls help me
An electrical firm manufactures light bulbs that have a length of life that is approximately normally distributed with a standard deviation of 35 hours. If a sample of 50 bulbs has an average life of 730 hours, find a 96% confidence interval for the population mean of all bulbs produced by this firm. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table....