Question

atch Corporation of Switzerland claims that its watches on average will neither gain nor lose time during a week. A sample of 18 watches provided the following gains (+) or losses (−) in seconds per week. Picture Click here for the Excel Data File −0.21 −0.19 −0.15 −0.16 +0.25 −0.24 +0.32 +0.43 −0.15 −0.39 −0.41 −0.55 −0.52 −0.67 −0.05 −0.28 −0.26 +0.03

State the null hypothesis and the alternate hypothesis.

State the decision rule for 0.05 significance level. (Negative amounts should be indicated by a minus sign. Round your answers to 3 decimal places.)

Compute the value of the test statistic. (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.)

Is it reasonable to conclude that the mean gain or loss in time for the watches is 0? Use the 0.05 significance level

. Estimate the p-value.

Answer 1

gainy loss Decision solution or Hol M=0 ve Hii no fos monteres Let T be the appropriate test Statistic for testing the above hypothesis. T= X-M S/NT8 Decision or b-value is less than 0.05 thon Ho. Otherwise beject Ho ~ + 18-1 If the we re accept Ho.

sy value of test test statistichet under to: M=0. is to X-0 · Ros-014748 do 50.2951282 B01118 -2.55566 ~ -2.556 47 vatnet [12) axmin { Platy to: 025;y 1pc + <-%0.025317)} 2x min&P(+7021098/6) /P(+<73104216) 2X min {0/025, 0./025 p-value = 2 ximin {p(ty-2.556) PC FC 2.556) 2xmin {0.0102248,01 19894422 28 0.0102278 000204556 ~0.0201 Since p-value is less than 0.05 and conclude We reject to that mean gain or loss in time for the watches is at ha 5% significance level = 도 E not zero