Third time asking this question. It's a doozy apparently. Hoping someone can lock it down for me! Assume none of the answers you see are correct. Appreciate the help :)
Homework Answers
![a. The hypotheses are correct. b. The critical values are calculated in R as shown below: > qt (0.05/2,17) [1] -2.109816 > qt](http://img.homeworklib.com/questions/5a9713d0-bb68-11ea-8a37-8d4c689a7c9e.png?x-oss-process=image/resize,w_560)
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Third time asking this question. It's a doozy apparently. Hoping
someone can lock it down for...
atch Corporation of Switzerland claims that its watches on average will neither gain nor lose time...
atch Corporation of Switzerland claims that its watches on average will neither gain nor lose time during a week. A sample of 18 watches provided the following gains (+) or losses (−) in seconds per week. Picture Click here for the Excel Data File −0.21 −0.19 −0.15 −0.16 +0.25 −0.24 +0.32 +0.43 −0.15 −0.39 −0.41 −0.55 −0.52 −0.67 −0.05 −0.28 −0.26 +0.03 State the null hypothesis and the alternate hypothesis. State the decision rule for 0.05 significance level. (Negative amounts...
Watch Corporation of Switzerland claims that its watches on average will neither gain nor lose time...
Watch Corporation of Switzerland claims that its watches on average will neither gain nor lose time during a week. A sample of 18 watches provided the following gains (+) or losses (−) in seconds per week. Click here for the Excel Data File −0.21 −0.17 −0.17 −0.23 +0.31 −0.28 +0.44 +0.37 −0.19 −0.35 −0.56 −0.44 −0.47 −0.60 −0.04 −0.28 −0.24 +0.03 State the null hypothesis and the alternate hypothesis. State the decision rule for 0.10 significance level. (Negative amounts should...
Watch Corporation of Switzerland claims that its watches on average will neither gain nor lose time...
Watch Corporation of Switzerland claims that its watches on average will neither gain nor lose time during a week. A sample of 18 watches provided the following gains (+) or losses (−) in seconds per week. −0.43 −0.22 −0.42 −0.37 +0.27 −0.23 +0.32 +0.54 −0.19 −0.29 −0.34 −0.55 −0.44 −0.56 −0.05 −0.19 −0.24 +0.08 Compute the value of the test statistic. (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.) Is it reasonable...
A shopping centre wants to examine the amount of space required for parking. Studies indicated that...
A shopping centre wants to examine the amount of space required for parking. Studies indicated that 61% of staff and shoppers use public transportation. A survey of 1,002 was taken, and 580 responded that they used public transportation. a. State the null hypothesis and the alternate hypothesis. Round the final answers to 2 decimal places. H0: p = H1: p ≠ b. State the decision rule for 0.05 significance level. (Negative answer should be indicated by a minus sign. Round...
According to the Census Bureau, 3.34 people reside in the typical American household. A sample of...
According to the Census Bureau, 3.34 people reside in the typical American household. A sample of 26 households in Arizona retirement communities showed the mean number of residents per household was 2.70 residents. The standard deviation of this sample was 1.17 residents. At the 10 significance level, is it reasonable to conclude the mean number of residents in the retirement community household is less than 3.34 persons? a. State the null hypothesis and the alternate hypothesis. (Round your answer to...
n order to conduct a hypothesis test for the population proportion, you sample 480 observations that...
n order to conduct a hypothesis test for the population proportion, you sample 480 observations that result in 264 successes. (You may find it useful to reference the appropriate table: z table or t table) Ho: pz 0.60 HA: p0.60 a-1. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.) Test statistic 2.24 a-2. Find the p-value....
The following hypotheses are given. HO: IT = 0.40 HAT+0.40 A sample of 120 observations revealed...
The following hypotheses are given. HO: IT = 0.40 HAT+0.40 A sample of 120 observations revealed that p=0.30. At the 0.05 significance level, can the null hypothesis be rejected? a. State the decision rule. (Negative amounts should be indicated by a minus sign. Round your answers to 2 decimal places.) Reject HO and accept H1 when z< or z> b. Compute the value of the test statistic. (Negative amount should be indicated by a minus sign. Round your answer to...
In order to conduct a hypothesis test for the population proportion, you sample 320 observations that...
In order to conduct a hypothesis test for the population proportion, you sample 320 observations that result in 128 successes.(You may find it useful to reference the appropriate table: z table or t table HO pz 0.45; HA: p < 0.45. a-1. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.) est statistic a-2. Find the p-value....
A cell phone company offers two plans to its subscribers. At the time new subscribers sign...
A cell phone company offers two plans to its subscribers. At the time new subscribers sign up, they are asked to provide some demographic information. The mean yearly income for a sample of 43 subscribers to Plan A is $58,200 with a standard deviation of $9.000. This distribution is positively skewed: the coefficient of skewness is not larger. For a sample of 42 subscribers to Plan B. the mean income is $58.400 with a standard deviation of $8.700. At the...
Chpt 9 Assignment i Saved Exercise 9-56 A shopping centre wants to examine the amount of...
Chpt 9 Assignment i Saved Exercise 9-56 A shopping centre wants to examine the amount of space required for parking. Studies indicated that 52% of staff and shoppers use public transportation. A survey of 1,002 was taken, and 480 responded that they used public transportation. 10 points a. State the null hypothesis and the alternate hypothesis. Round the final answers to 2 decimal places. Ho: p = H1: p7 eBook Ask b. State the decision rule for 0.02 significance level....
According to the Census Bureau, 3.34 people reside in the typical American household. A sample of 26 households in Arizona retirement communities showed the mean number of residents per household was 2.70 residents. The standard deviation of this sample was 1.17 residents. At the 10 significance level, is it reasonable to conclude the mean number of residents in the retirement community household is less than 3.34 persons? a. State the null hypothesis and the alternate hypothesis. (Round your answer to...
n order to conduct a hypothesis test for the population proportion, you sample 480 observations that result in 264 successes. (You may find it useful to reference the appropriate table: z table or t table) Ho: pz 0.60 HA: p0.60 a-1. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.) Test statistic 2.24 a-2. Find the p-value....
The following hypotheses are given. HO: IT = 0.40 HAT+0.40 A sample of 120 observations revealed that p=0.30. At the 0.05 significance level, can the null hypothesis be rejected? a. State the decision rule. (Negative amounts should be indicated by a minus sign. Round your answers to 2 decimal places.) Reject HO and accept H1 when z< or z> b. Compute the value of the test statistic. (Negative amount should be indicated by a minus sign. Round your answer to...
In order to conduct a hypothesis test for the population proportion, you sample 320 observations that result in 128 successes.(You may find it useful to reference the appropriate table: z table or t table HO pz 0.45; HA: p < 0.45. a-1. Calculate the value of the test statistic. (Negative value should be indicated by a minus sign. Round intermediate calculations to at least 4 decimal places and final answer to 2 decimal places.) est statistic a-2. Find the p-value....
A cell phone company offers two plans to its subscribers. At the time new subscribers sign up, they are asked to provide some demographic information. The mean yearly income for a sample of 43 subscribers to Plan A is $58,200 with a standard deviation of $9.000. This distribution is positively skewed: the coefficient of skewness is not larger. For a sample of 42 subscribers to Plan B. the mean income is $58.400 with a standard deviation of $8.700. At the...
Chpt 9 Assignment i Saved Exercise 9-56 A shopping centre wants to examine the amount of space required for parking. Studies indicated that 52% of staff and shoppers use public transportation. A survey of 1,002 was taken, and 480 responded that they used public transportation. 10 points a. State the null hypothesis and the alternate hypothesis. Round the final answers to 2 decimal places. Ho: p = H1: p7 eBook Ask b. State the decision rule for 0.02 significance level....
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