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The null hypothesis and the alternate hypothesis are: Ho: The frequencies are equal. Hi: The frequencies are not equal. Categ

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the alternate hypothesis (1 are : The null hypothesis and Ho : The frequencies are equal. H: The frequencies are not equal CaX - test statistic (Fox - fer) 1 f. Under Ho, frequencies are given below, ECA) = 80xL 4 ECB) = 8ox t 4 E (c) Soxha 4 E(D) =p under Ho 3 2012 vo6005) From the chi Square table VI 10:05) = (005) = 7.815 We reject the null hypothesis if tabulated le.

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