Question

1. suppose a man applies a 60N force to a 50 KG stack of waves at an angle of 45° above the horizontal. He manages to pull the way to 10 m. Compute the speed of the stack of weights after the 10 m if the stack started from rest

2. if your leg exerts a force of nine and as it moves 0.4 M within 0.2 seconds, what is the power generated by your leg?

3. The applied force parallel to a surface is 200N in the applied force perpendicular to the surface is 575 N. The coefficient of friction is 0.66. What is the frictional force?

Suppose a man applesa con force to a sok stack of weights at an angle of 45 degrees above the horizontal, He manages to pull the weights 10 m.Compute the speed of the stack of weights after the 10mm if the stack started from rest A2.15 ms B. 1.71m's C. 4.12 s 0.3.73 ms QUESTION 14 your leg exerts a force of N as it moves .Am within 0.2 sec What is the power generated by your A 45W B.18 W C0.72 W D.45 W QUESTION 15 The applied force parallel to a surfaces 200 and the applied force perpendicular to the surface is 575. The coefficient of friction is 0.06. What is the cal force A 379.5N 0.132 N C. 250.5 N D.511.5N

Answer 1

1 → The horizontal force acting on the Stack is expressed as follows, Fa= F cose = F cosa F cosa ma = (60N)cos 45 50kg = 0.8485m/s2 Final speed of the stack after covers a distance of 10 mis, = 2as 2 V = Vas = 2(0.8485 m/s> )(10m) = 4.12 m/s * Threfore, out of all correct option is (c)* 2 → Power generated by the leg is the rate of doing work done by him. P= Fs = (9N) (0.4m) 0.2s = 18W Threfore, out of all correct option is (B)* 3 → Mathematical expresstion for Frintional force is , f = UN Here, Nnormal reaction is perpendicular force(F.) acting on surafce. f = 47 = (0.66) (575N) = 379.5N Threfore, out of all correct option is (A)* =