Question

A researcher wants to study the relationship between salary and gender. She randomly selects 324 individuals and determines t
Step 1 of 8: State the null and alternative hypothesis. < Answer 2 Points Tables Prev Keybo Ho: Salary and gender are depende
Step 2 of 8: Find the expected value for the number of men with an income below $25,000. Round your answer to one decimal pla
Step 3 of 8: Find the expected value for the number of women with an income below $25,000. Round your answer to one decimal p
Step 4 of 8: Find the value of the test statistic. Round your answer to three decimal places. Answer (How to Enter) 1 Point I
Step 5 of 8: Find the degrees of freedom associated with the test statistic for this problem. Answer How to Enter) 2 Points T
Step 6 of 8: Find the critical value of the test at the 0.1 level of significance. Round your answer to three decimal places.
Step 7 of 8: Make the decision to reject or fail to reject the null hypothesis at the 0.1 level of significance. Answer Point
Prev Step 8 of 8: State the conclusion of the hypothesis test at the 0.1 level of significance. Answer 1 Point Tables Keyboar
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Answer #1
Given table data is as below
MATRIX col1 col2 TOTALS
row 1 26 24 50
row 2 34 38 72
row 3 42 47 89
row 4 53 60 113
TOTALS 155 169 324
------------------------------------------------------------------

calculation formula for E table matrix
E-TABLE col1 col2
row 1 row1*col1/N row1*col2/N
row 2 row2*col1/N row2*col2/N
row 3 row3*col1/N row3*col2/N
row 4 row4*col1/N row4*col2/N
------------------------------------------------------------------

expected frequencies calculated by applying E - table matrix formulae
E-TABLE col1 col2
row 1 23.92 26.08
row 2 34.444 37.556
row 3 42.577 46.423
row 4 54.059 58.941
------------------------------------------------------------------

calculate chisquare test statistic using given observed frequencies, calculated expected frequencies from above
Oi Ei Oi-Ei (Oi-Ei)^2 (Oi-Ei)^2/Ei
26 23.92 2.08 4.326 0.181
24 26.08 -2.08 4.326 0.166
34 34.444 -0.444 0.197 0.006
38 37.556 0.444 0.197 0.005
42 42.577 -0.577 0.333 0.008
47 46.423 0.577 0.333 0.007
53 54.059 -1.059 1.121 0.021
60 58.941 1.059 1.121 0.019
ᴪ^2 o = 0.413
------------------------------------------------------------------

set up null vs alternative as
null, Ho: no relation b/w X and Y OR X and Y are independent
alternative, H1: exists a relation b/w X and Y OR X and Y are dependent
level of significance, α = 0.1
from standard normal table, chi square value at right tailed, ᴪ^2 α/2 =6.251
since our test is right tailed,reject Ho when ᴪ^2 o > 6.251
we use test statistic ᴪ^2 o = Σ(Oi-Ei)^2/Ei
from the table , ᴪ^2 o = 0.413
critical value
the value of |ᴪ^2 α| at los 0.1 with d.f (r-1)(c-1)= ( 4 -1 ) * ( 2 - 1 ) = 3 * 1 = 3 is 6.251
we got | ᴪ^2| =0.413 & | ᴪ^2 α | =6.251
make decision
hence value of | ᴪ^2 o | < | ᴪ^2 α | and here we do not reject Ho
ᴪ^2 p_value =0.938


ANSWERS
---------------
null, Ho: no relation b/w X and Y OR X and Y are independent
alternative, H1: exists a relation b/w X and Y OR X and Y are dependent
test statistic: 0.413
critical value: 6.251
p-value:0.938
decision: do not reject Ho

we do not have enough evidence to support the claim that there is a relationship between income and gender.

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