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PLEASE HELP WITH THE WHITE BOX QUESTIONS & THE HIGHLIGHTED
YELLOW AREA. BOLD THE ANSWERS PLEASE...
A vinegar titration was completed using a pH meter as an indicator of the changing pH....
A vinegar titration was completed using a pH meter as an indicator of the changing pH. A 25.00 mL sample of diluted vinegar (diluted by a factor of 5) was placed in a beaker and subsequently titrated with 0.1098 M NaOH. A derivative curve of the titration suggested that the equivalence point occurred at 40.90 mL. Calculate the mass percent of CH_3COOH. (The density of vinegar is 1.008 g/mL.) Moles of base at the equivalence point = Moles of acid...
If you could please help me with these that would be amazing! Thanks in advance Pre-Lab...
If you could please help me with these that would be
amazing! Thanks in advance
Pre-Lab Assignment for Experiment 19:Titration Curves Introduction: This pre-lab assignment will illustrate some of the important features of titration curves and what information can be obtained from them. A titration curve is the plot of the pH of a solution such as an acid or a base as a titrant is being added to it. A titrant is the solution being added from a buret,...
i need help with questions for part b only please ZULU Acid-Base Titration (worksheet to be...
i need help with questions for part b only please
ZULU Acid-Base Titration (worksheet to be completed in pairs - dee via e-mail Thursday, April 2, 11:59 pm) Concentration of NaOH: 0.0993 mol/L Part A: The following data was obtained when a 20.00 mL sample of acetic acid was titrated with 0.0993 mol/L sodium hydroxide (NaOH). The indicator changed color when 18.90 mL of NAOH was added (highlighted below). pH pH Volume of Base (mL) 1.00 2.00 Volume of Base...
A Weak Acid - Strong Base Titration Report Sheet Date: Name: Volume of CH3COOH (ml): Sample...
A Weak Acid - Strong Base Titration Report Sheet Date: Name: Volume of CH3COOH (ml): Sample Code: { 10.00 mL Temperature: _22.0_ Initial Volume of NaOH (mL): 0.00 Molarity of NaOH (from label): _0.1013__ RUN 1 From LabQuest Titration Curve From 1st Derivative From Printed Titration Curve Instructor's Approval of LabQuest Data Volume of NaOH at Equivalence Pt (mL) 12.00mL 12.65mL Average Volume of NaOH at Equivalence Pt Include printed graphs of titration curve and 1st Derivation with Report Sheet...
molariity of NaOH is 0.09591 M Font 1.1. Paragraph 4.1 .5. 1. .2 . 1.1 ...6...
molariity of NaOH is 0.09591 M
Font 1.1. Paragraph 4.1 .5. 1. .2 . 1.1 ...6 Table 1. Raw Data Trial 1 Trial 2 unknown acid un acid mass of unknown acid transferred to beaker(@) 0.589 0.556 concentration of NaOH titrant solution (M) equivalence point volume of NaOH titrant (mL) 26.67 ml 26.16 ml half-equivalence point volume of NaOH titrant (mL) 13.84 ml 13.08 ml half-equivalence point pH 4.91 pH 5.14 pH 1. Calculate the moles of NaOH delivered at...
Part 4: Calculating pH values as a Titration Progresses - this is a tough question! Finally, consider a 20.00...
Part 4: Calculating pH values as a Titration Progresses - this is a tough question! Finally, consider a 20.00 mL aqueous solution of 0.20 M H2A, where "H2A" is some arbitrary diprotic acid (Ka1 = 4.35 x 10-7, Kaz = 4.85 x 10-11 Estimate the pH values of the solution after the addition of 0.00, 10.00, 20.00, 30.00, 40.00, and 60.00 mL of 0.20 M NaOH. d) Calculation M4 - 30.00 ml NaOH Added: Here we realize that 20 ml...
During the titration the following reaction occurs HA + NaOH = NaA+H2O What is the concentration...
During the titration the following reaction occurs HA + NaOH = NaA+H2O What is the concentration of A (the conjugate base of the weak acid) at the equivalence point? M Use [A] and the pH at the equivalence point to estimate Ko of the weak acid (this is the hard way of estimating K.) Use the pH at the half-way point to estimate of the weak acid (this is the easier way) Your grade will be shown after clicking 'Grade'...
Please help. I am studying for an upcoming exam and I am having a hard time...
Please help. I am studying for an upcoming exam and I am having
a hard time doing these two questions.
21-90. What is the pH of the solution that results from the addition of 25.0 mL of 0.200 M KOH(aq) to 50.0 mL of 0.150 M HNO,(aq)? 21-67. A 2.500-gram sample of oxalic acid, a diprotic acid, is dissolved in 250.0 mL of water and titrated with 1.000 M NaOH(aq) to the first equivalence point. The volume of base required...
the concentration is .1000 M for NaOH. you cN disregard the second column. but there is...
the
concentration is .1000 M for NaOH. you cN disregard the second
column. but there is no further information.
equivalence point is 22.95. i dont have mL NaOH
this is all i have
DATA TABLE sor CHCOOH Trial Volume CHCOOH (ml) [NTOH (M) Equivalence point Md point (ML) (ml) NE 100CM 1000M a.so DATA ANALYSIS moles -(CX) 1. Calculate the number of moles of NaOH used in the reaction with the acetic acid (CH.COOH) solution . OOON NaoH 2. How...
50.0 mL sample of the weak acid the concentration of the weak acid = 0.15 M...
50.0 mL sample of the weak acid
the concentration of the weak acid = 0.15 M
25 mL of the week acid into 100 mL beaker
titrated this solution of 0.21 M NaOH
moles of weak acid = 3.75*10^-3
moles of NaOH = moles of week acid
c) How many milliliters of the NaOH are required to neutralize the sample of weak acid? d) How many moles of NaOH have been added at one half of the volume in part...
A vinegar titration was completed using a pH meter as an indicator of the changing pH. A 25.00 mL sample of diluted vinegar (diluted by a factor of 5) was placed in a beaker and subsequently titrated with 0.1098 M NaOH. A derivative curve of the titration suggested that the equivalence point occurred at 40.90 mL. Calculate the mass percent of CH_3COOH. (The density of vinegar is 1.008 g/mL.) Moles of base at the equivalence point = Moles of acid...
If you could please help me with these that would be
amazing! Thanks in advance
Pre-Lab Assignment for Experiment 19:Titration Curves Introduction: This pre-lab assignment will illustrate some of the important features of titration curves and what information can be obtained from them. A titration curve is the plot of the pH of a solution such as an acid or a base as a titrant is being added to it. A titrant is the solution being added from a buret,...
i need help with questions for part b only please
ZULU Acid-Base Titration (worksheet to be completed in pairs - dee via e-mail Thursday, April 2, 11:59 pm) Concentration of NaOH: 0.0993 mol/L Part A: The following data was obtained when a 20.00 mL sample of acetic acid was titrated with 0.0993 mol/L sodium hydroxide (NaOH). The indicator changed color when 18.90 mL of NAOH was added (highlighted below). pH pH Volume of Base (mL) 1.00 2.00 Volume of Base...
A Weak Acid - Strong Base Titration Report Sheet Date: Name: Volume of CH3COOH (ml): Sample Code: { 10.00 mL Temperature: _22.0_ Initial Volume of NaOH (mL): 0.00 Molarity of NaOH (from label): _0.1013__ RUN 1 From LabQuest Titration Curve From 1st Derivative From Printed Titration Curve Instructor's Approval of LabQuest Data Volume of NaOH at Equivalence Pt (mL) 12.00mL 12.65mL Average Volume of NaOH at Equivalence Pt Include printed graphs of titration curve and 1st Derivation with Report Sheet...
molariity of NaOH is 0.09591 M
Font 1.1. Paragraph 4.1 .5. 1. .2 . 1.1 ...6 Table 1. Raw Data Trial 1 Trial 2 unknown acid un acid mass of unknown acid transferred to beaker(@) 0.589 0.556 concentration of NaOH titrant solution (M) equivalence point volume of NaOH titrant (mL) 26.67 ml 26.16 ml half-equivalence point volume of NaOH titrant (mL) 13.84 ml 13.08 ml half-equivalence point pH 4.91 pH 5.14 pH 1. Calculate the moles of NaOH delivered at...
Part 4: Calculating pH values as a Titration Progresses - this is a tough question! Finally, consider a 20.00 mL aqueous solution of 0.20 M H2A, where "H2A" is some arbitrary diprotic acid (Ka1 = 4.35 x 10-7, Kaz = 4.85 x 10-11 Estimate the pH values of the solution after the addition of 0.00, 10.00, 20.00, 30.00, 40.00, and 60.00 mL of 0.20 M NaOH. d) Calculation M4 - 30.00 ml NaOH Added: Here we realize that 20 ml...
During the titration the following reaction occurs HA + NaOH = NaA+H2O What is the concentration of A (the conjugate base of the weak acid) at the equivalence point? M Use [A] and the pH at the equivalence point to estimate Ko of the weak acid (this is the hard way of estimating K.) Use the pH at the half-way point to estimate of the weak acid (this is the easier way) Your grade will be shown after clicking 'Grade'...
Please help. I am studying for an upcoming exam and I am having
a hard time doing these two questions.
21-90. What is the pH of the solution that results from the addition of 25.0 mL of 0.200 M KOH(aq) to 50.0 mL of 0.150 M HNO,(aq)? 21-67. A 2.500-gram sample of oxalic acid, a diprotic acid, is dissolved in 250.0 mL of water and titrated with 1.000 M NaOH(aq) to the first equivalence point. The volume of base required...
the
concentration is .1000 M for NaOH. you cN disregard the second
column. but there is no further information.
equivalence point is 22.95. i dont have mL NaOH
this is all i have
DATA TABLE sor CHCOOH Trial Volume CHCOOH (ml) [NTOH (M) Equivalence point Md point (ML) (ml) NE 100CM 1000M a.so DATA ANALYSIS moles -(CX) 1. Calculate the number of moles of NaOH used in the reaction with the acetic acid (CH.COOH) solution . OOON NaoH 2. How...
50.0 mL sample of the weak acid
the concentration of the weak acid = 0.15 M
25 mL of the week acid into 100 mL beaker
titrated this solution of 0.21 M NaOH
moles of weak acid = 3.75*10^-3
moles of NaOH = moles of week acid
c) How many milliliters of the NaOH are required to neutralize the sample of weak acid? d) How many moles of NaOH have been added at one half of the volume in part...
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