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Short Answer Question We have a dataset with n - 10 pairs of observations (x, y), and 683, -813, -47,405, 1.4 - 56,089 - 66,7

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Answer #1
n= 10
Σx= 683
Σx2 = 47405
Σy = 813
Σy2 = 66731
Σxy= 56089
SSx=Σx2-(Σx)2/n= 756.1000
SSy=Σy2-(Σy)2/n= 634.1000
SP=Σxy-(ΣxΣy)/n= 561.1000
b1= SP/Sxx = 0.7421
b=(Σy-bo*Σx)/n= 30.6147
SSE =Syy-(Sxy)2/Sxx= 217.7090
σ̂2=SSE/(n-2)= 27.2136
σ̂=√σ̂2= 5.21667
predicted value at X=90 is:0.7421*90+30.6147= 97.404
standard error of CI=s*√(1/n+(x0-x̅)2/Sxx)= 4.4351
for 99 % CI value of t= 3.3550 (from excel:tinv(0.01,8)
margin of error E=t*std error= 14.8796
lower confidence bound=xo-E= 82.5239
Upper confidence bound=xo+E= 112.2831

95% confidence interval =(82.5239 , 112.2831)

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