Question

Air-USA has a policy of booking as many as 24 persons on an airplane that can seat only 22. Past studies have revealed that only 88% of the booked passengers actually arrive for the flight.) Find the probability that if Air-USA books 24 persons, not enough seats will be available. prob - Is this probability low enough so that overbooking is not a real concern for passengers if you define unusual as 5% or less Ono, it is not low enough to not be a concern Oyes, it is low enough not to be a concern What about defining unusual as 10% or less? Oyes, it is low enough not to be a concern O no, it is not low enough to not be a concern

Answer 1

solution:- n mo p=0.088 m = 24 P(x) = 2 kq in Binomial 124 ;0.089 a) p (mol enough seals) = P1(1) = P1X=0)+ P 1x = 1) (24)(0.088)10.91237129)10.080609123 튼 0.3635 No, it is not low enough to not be concern No, it is not low enogh to not becomla B ). xn Bimonial (15; 0.073) 1) 4 0.0168 9) P\x=4) - 1'?) (0.093) (0.927) 2 x 15-X by P1x23) (0.093) (0.929) = 0.9085 X=0 row 15 x loow 15- Oplx>3) - I (5) (0.073) (0.927) 0.0202 X=4 15-X dy P1x23) = 3/5 18 0.7 1.8245 0.9798