Question

Sie The average score of all golfers for a particular course has a mean of 68 and a standard deviation of 3.5. Suppose 49 golfers played the course today. Find the probability that the average score of the 49 golfers exceeded 69. Round to four decimal places. O A. 0.0228 OB. 0.4772 OC. 0.1293 ch D. 0.3707

Answer 1

soluton, Given meas u: 68 standard deviation o: 3.5 Random sample sisa Now, probability that average score of 19 golfers exceeded 69 P(x>69) = 1-P(2269) e. 69-68 < ---02*** 3.5/29 11P/zás) 1-P (222) I- 0.9772 = 0,0228 Plus a> 69): 0.0 228 opton A

2 Given mean u=713 Standard deviaton 0:2.7 Bandom sample 0:36 probability that they have a mean height greader than 72,3 P(*>72.3). 1-P(xc 72. 3) 72, 3 - 77.3 -1-ola 21/8 :1-P(2<dés) : 1-P/2c 2.8571) : 0.0021 1-0.9979 Le P(x>72,3): 0.0021 option