The average score of all golfers for a particular course has a mean of 75 and...
Sie The average score of all golfers for a particular course has a mean of 68 and a standard deviation of 3.5. Suppose 49 golfers played the course today. Find the probability that the average score of the 49 golfers exceeded 69. Round to four decimal places. O A. 0.0228 OB. 0.4772 OC. 0.1293 ch D. 0.3707 Assume that the heights of men are normally distributed with a mean of 71.3 inches and a standard deviation of 2.1 inches. If...
The average score of all golfers for a particular course has a mean of 76 and a standard deviation of 5. Suppose 100 golfers played the course today. Find the probability that the average score of the 100 golfers exceeded 77.
The average score of all pro golfers for a particular course has a mean of 71 and a standard deviation of 3.0. Suppose 36 pro golfers played the course today. Find the probability that the average score of the 36 pro golfers is less than 70. (Use 4 decimals)
The average score of all golfers for a particular course has a mean of 66 and a standard deviation of 5. Suppose 100 golfers played the course today. Find the probability that the average score (a) Find the mean of the sampling distribution for the average score (sample mean) of 100 golfers. Round answer to the nearest integer. Do NOT include the zero before the decimal point. Mean = ____ (b) Find the standard deviation of the sampling distribution...
1.) 2.) 3.) To assess attitudes towards issues that affect the residents of a village, the village randomly chose 800 families to participate in a survey of life attitudes the village received 628 completed surveys what is the sample proportion of completed surveys? 0.628 0.785 1.274 0.886 Describe the sampling distribution of p. Round to three decimal places when necessary. N=25,000, n=200, p = 0.6 O A. Approximately normal; Hp = 0.6, Op = 0.035 OB. Exactly normal; Hp =...
hapter 8: Sampling Distribution 1. The distribution of i is normal: n 2 30. 2. Be able to find the mean of sample means: Hx =H 3. Be able to find the standard deviation of sample means: Ox = %3D 4. Be able to distinguish and find the probability for an individual value x and a group x. 5. Be able to distinguish and find an individual value x or a group average £ from a given probability. 6. Examples...
Suppose we are interested to construct a 95% confidence interval of the mean exam score. A random sample of 36 scores is taken and gives a sample mean (sample mean score) of 68. EBM will be the largest O a when the population standard deviation is 12 points, when the population standard deviation is 18 points. OC when the population standard deviation is 15 points when the population standard deviation is 20 points Od b. Suppose we are interested to...
Historically, the average score of PGA golfers for one round is 65.9 with a standard deviation of 3.56. A random sample of 104 golfers is taken. What is the probability that the sample mean is greater than 65.6?
(1 point) Use the following information for all parts of this problem. On a particular golf course, a sample of 44 golfers have a mean golf score of 83. Suppose the population standard deviation for this course is 4.72 Part 1: Part 2: Using the formula from part 1, find a 95% confidence interval for the mean golf score of all golfers. Round each answer to the nearest hundredth (2 decimal places) to
Question 8 (1 point) Historically, the average score of PGA golfers for one round is 73.9 with a standard deviation of 1.1. A random sample of 99 golfers is taken. What is the probability that the sample mean is between 73.9 and 74.03? 1) 1.3802 2) 0.3802 3) -1.8011 4) The sample mean will never fall in this range 5)00470