Homework Answers
Answer:
Given,
To determine the probability that the average score of 36 pro golfers is lessthan 70
Here mean = 71
standard deviation = 3
n = 36
sqrt(n) = 6
Now,
P(xbar < 70) = P(Z < (70 - mean) /(s/sqrt(n)))
substitute the values
= P(Z < 70 - 71/( 3/6))
= P(Z < - 2)
Required probability = 0.0228
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