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2. a) In the isosceles trapezoid below, we have ZBAC = LBDC = 90, AE = 5 cm, DC = 12 cm. Find BC. D E B С b) In the figure b

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(a) In the isoscales trapezoid ABCDE A D Sem 90° 9 of 12.5mg 12cm 130m 130m с B LBACE < BOC = 90 AE = = som DC = 12cm in the(b) A goo 320 142° 33° 900 90° BB 90 с. 33 1440 57° IS ABCD is an rectangle BE a AB LBED = 57° L BAD = 90° LADCE LD C B = go6 (c) In the Rhombus 60° 30° А 25 2x .242 Sie 38 900 →30° 90- Taxi 5 Goo 52x7 C 30 B GOO 19 < DAC ae L ABD = 27° + All the siЧX+ ЧX-MX - 360 12 X = 360 of 360° 12 ox 30 23° = 60° since LBACE CAD CDCA = CBCA = 30° LADB = LBDC -LDBA=<DBC 60°the sum of all the angles in the triangle is 180degree

Sum of angles in the rhombus is 360degree

In the rhombus diagonals bisect at 90degree

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