Question

QUESTION 24 4 points A study conducted by a commuter train transportation authority involved surveying a random sample of 200 passengers. The results show that a customer had to wait on the average 9.3 minutes with a standard deviation of 6.2 minutes to buy his or her ticket. Construct a 95% confidence interval for the true mean waiting time. What is the lower confidence limit? 4 points S QUESTION 25 An airport bus driver conducted a study to see what proportion of customers use the shuttle bus to get to and from the parking lot. The results of his study are listed below, where B - customer used the bus and W = customer walked BBBWWBB WWW WBBBBB WBBB WWBBBBWBWB WWBBWWBWWB BBBBBBBW Construct a 90% confidence interval for p, the true proportion of all people who used the bus. What is the lower confidence limit for p?

Answer 1

My dear student I am allow to solve one question at a one time so I solved first one (as per HOMEWORKLIB POLICY)

no 200 X = 9.3 Se 6.2 Confidence interval = 0.95 d=1-0-95=0.05 2/2 = = 0.025 Population Standard deviation is unknown so will use t-table distribution. [df = n-1= 200-1 = 199] tesitical = txandfa to.ogg3199 = 1):972 (using t-table) 95% confidence interval Lowed limit'- x-ta/edf* Jn = 9.3-1.972 * 6:2 1200 = 9.3-0.8645 Lower limit=18.4355 8.4355]- Ang.