Question

The data show systolic and diastolic blood pressure of certain people. Find the regression equation, letting the systolic reading be the independent (x) variable. Find the best predicted diastolic pressure for a person with a systolic reading of 118. Is the predicted value close to 74.2, which was the actual diastolic reading? Use a significance level of 0.05. Systolic Diastolic Click the icon to view the critical values of the Pearson correlation coefficient r. 150 109 124 91 149 110 120 85 114 82 135 74 136 72 116 87 What is the regression equation? ỹ=+x (Round to two decimal places as needed.) What is the best predicted diastolic pressure for a person with a systolic reading of 118? The best predicted diastolic pressure for a person with a systolic reading of 118 is (Round to one decimal place as needed.) Is the predicted value close to 74.2, which was the actual diastolic reading? O A. The predicted value is not close to the actual diastolic reading. O B. The predicted value is very close to the actual diastolic reading. OC. The predicted value is close to the actual diastolic reading. OD. The predicted value is exactly the same as the actual diastolic reading.

Answer 1

Let

systolic be x and

diastolic be y

x : 150 124 149 120 114 135 136 116

y : 109 91 110 85 82 74 72 87

X - My Y - My 19.5 -6.5 18.5 - 10.5 -16.5 4.5 5.5 - 14.5 20.25 2.25 21.25 -3.75 -6.75 - 14.75 -16.75 -1.75 (X - Mx)2 380.25 42.25 342.25 110.25 272.25 20.25 30.25 210.25 (X - Mx)(Y - My) 394.875 - 14.625 393.125 39.375 111.375 -66.375 -92.125 25.375 SS: 1408 SP: 791

from the above data Ex = 1044 Ey - 710 Mego Mx = 130.5 my = 88.75 Regression equation = = bata where b= spissa -19111408 = 0·56179 a = my-bmx = 88.75-10-56 X130.5) - 15.43643 Therefore Jo = 15.44 +0.56%

b) - 15:44 + 0-56 x -15.44 +0.56 X 118 = 81.52 81.5 The best predicted diastolic for a person person with a systolic reading of 118 is 81,5, option A) The predicted value is not close to the diastolic reading. actual