Question

The data show systolic and davol blood pressure of certain people. Find the regression equation letting the st is the predicted value does lo 69.0, which was the actual diastolic roading? Use agricance level of 0.05. reading bete independent variabile Find the best predicted distresu for a persona t g e 150 Diastolle Cok the loon to view the co 101 102 104 3 u es of the Pearson correlation coefficient 74 What is the regression equation? Y o und to two decimal places as needed.) What is the best predicted to pressure for a person with a wysorong of 10 The best predicted to pressure for a person with a s ol reading of 150 (Hound to one decimal place as needed.) is the predicted value close to 600, which was the actual diastolic reading? OA The predicted value is very close to the actual diastolic reading OB. The predicted value is close to the actual diastolic reading. OC. The predicted value is not close to the actual diastolic reading. OD The predicted value is exactly the same as the actual diastolic reading

Answer 1

The independent variable is X, and the dependent variable is Y. In order to compute the regression coefficients, the following table needs to be used: х Y X*Y X2 X2 139 101 14039 19321 10201 118 7198 13924 3721 145 11890 21025 6724 133 9842 17689 5476 141 14664 19881 10816 138 10902 19044 6241 139 10286 19321 5476 136 10064 18496 5476 Sum = 1089 649 88885 148701 54131 Based on the above table, the following is calculated: * = { x = 1959 = 136.125 Y = ÜY; = 649 = 81.125

58xx = x + ( x ) = 16701 – 1984/8 – 6.575 $$y = -(3x) = 54131 – 6497/8 = 1480.575 58x = $x*-+ (**) () = -485 – 1050 2 640/8 = 580 5875 SSXY =) X; D Y ) = 88885 – 1089 x 649/8 = 539.875 i=1 i=1 Therefore, based on the above calculations, the regression coefficients (the slope m, and the y- intercept n) are obtained as follows: SSXy539.875 m =ad SSxx 460 875 - 1.1714 n=Y - X.m = 81.125 - 136.125 x 1.1714 = -78.3336 Therefore, we find that the regression equation is: Y = -78.3336 +1.1714X

Regression equation :

$\small \hat{y} = 78.33+1.17\ x$

Now,

x = 150

So,

$\small \hat{y} = -78.33+1.17\ *150 =97.2$

Correct option : B. The predicted value is close to the actual diastolic reading