Question

please answer both 5 and 6 because they are connected

5) A real object is placed 4.0 cm away from a lens with a focal length f = 5.0 cm. Where is the image located? 6) In (5) is the image upright or inverted? Is it real or virtual? What is the magnification?

Answer 1

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U = -4.0cm (Real Image) f =+5.0cm ť = | - | 5 = 1/- (-10) Se the 음 4-5 = 1 V 5x4 -20 object V = 584 4-5 cm Image - 20cm towards the left side of lens is located located 20 cm from the lens (left side of so Image is magnification ha hi v u m = -20 -4 - 5 cm. 20 maquifpication is positive so Image will be upright the Amage forms on the same side of object therefore Image is virtual Auswers 2 Amage is upright, virtual with a mapurification of s.