Question

(a) Let X, have a chi-squared distribution with parameter V, and let X, be independent of X, and have a chi-squared distribut

ng Pylv) results in which of the following? -W/2 FAX) = 2e du / -u/2 O Fly) = + 1/2 - 1 e -1 (*3*3 (433) O FAN) - 1 1 (43-53

(b) It can be shown that if Z is a standard normal rv, then Z2 has a chi-squared distribution with v = 1. Let Z, Z2, ..., Z,

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Answer #1


Complete solution for the problem can be found in the images below with all the necessary steps.
Do give a thumbs up if you liked the solution. Thank You :)mG. f of y2 distra is i 1/2 2t).on MG-f of X, is M, (+) = Vila (1-25) & m.lf of yz is M (t) X2 V2/2 (1-2) then let mof of y * My (t) = Eleth Ele be My(t) tky> Hence by uniqueness of Mr Gof x, tita ~ V, +17) Y Now 1 Fyly) = P(x + x 2y) [ • YEY ax, +4₂29 P/X, S p z ya XEY*). y you, fa ) Xuitur random variable fy (4) is pay of V tuz Therefore, comparing get, the last option (option 5) is the correct form of2 2 . 21 +24 L (df = 2) x (d.f 3). 2 2 + 22 + 22+23 2 24 -+ 2. L icd 4,61) । 2 ।,2,-.) X D_X.- J/01). 7-12),2,-7n- 2 व 2 J4 7

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