Question

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The heat-pump system shown is designed to provide water-heating and space-cooling. The system includes a heat exchanger to subcool the R134a refrigerant at the outlet of the water heater while heating the refrigerant at the outlet of the evaporator. Given the following data, determine the enthalpy at each station, 1 through 6, using the R134a property tables (click here). Type your answers hy through h6 in the space provided below, and show all your work on your paper. · At the compressor inlet, T1 = 20°C and P1 = 320 kPa. • At the compressor outlet, T2 = 90°C and P2 = 2 MPa. · At the water heater outlet, the refrigerant is in a saturated-liquid state. · At the outlet of the evaporator, the refrigerant is in a saturated-vapor state. · The power supplied to the compressor is comp = 2.7 kW. evaporator section condenser section air flow Qcool P2, T2 AMAT water heater space cooling compressor (adiabatic) Qhw fan P5 = P6 insulated duct P6 = P1 sat. vapor piza 6) Wcomp throttle (adiabatic) heat exchanger (adiabatic) P1, T1 P3 = P2 sat.liquid P4 = P2 refrigerant R134a

Answer 1

Question:- evaporater section of us wath heater 3 ป 3 co Enthalpy hi [ kilkg] @ Ti = 20°C & P = 320kla = .32MPa 7,- 415.5 kilky {antes polation? Calc :- @ T. = 20°C Pi = '30 MPa n = 4 6 124 L ff = 413, 965 2:40 MPa) - @.32 MPa h@ .30 MPa t h@ .02 MP a 416.124 + 40Mta Ş h@. 3ompă he Pi - Pf X 0.02 416.124 + 416.124 - 413.965 002) (1) 415.5 kiing | Cappx) CS CamScanner Scanned with

(b) P₂ = 2MPa hz (kulkq) @ Topa 90°c Enthalpy ) R-134a steam table of supesheated Directly Read from 1h2 = 458.951 kJ/kg kring saturated liquid (C) At heater exit slate Refrigerant is fully hy @ P₂ = 1 = 2 MPa h z = h, @ P3 f ho = 299.9 kJ! kilig from R-134-a, property Table (a) considning The heat exchanger ☺ nf Hi 3 It is an eclosert cycle so samesce everywhere mase flow rate of the Refrigerant of

o Heat im Exchange nit Cha-hy) the Heat exchanger mg (horks) > ha hz = ho-hi hat hy = hotha eque © (e) Enthalpy ho h @ PG = P1 = .32MP. g from R134(Q) Table Property 399.98 kJ/kg ho we Putting ho in legn " Û & also put hi & hz - get the + 415.5 = 399,98 + 299.9 ha 284.5 kuling ( from state to state ② There is this: thosting process & throthing is isenthalbic process so, h5= hq = 284.5 ating. CS Scanned with CamScanner