Question

Quick help please

How long will it take the water-heater in Question 1 to raise the temperature of 200 liters of water from 20°C to 55°C?

The heat-pump system shown is designed to provide water-heating and space-cooling. The system includes a heat exchanger to subcool the R134a refrigerant at the outlet of the water heater while heating the refrigerant at the outlet of the evaporator. Given the following data, determine the enthalpy at each station, 1 through 6, using the R134a property tables (click here). Type your answers hy through hg in the space provided below, and show all your work on your paper. • At the compressor inlet, T = 20°C and P, = 200 kPa. • At the compressor outlet, T2 = 105°C and P2 = 1.8 MPa. • At the water-heater outlet, the refrigerant is in a saturated-liquid state. • At the outlet of the evaporator, the refrigerant is in a saturated-vapor state. • The power supplied to the compressor is Wc comp = 3.3 kW

Answer 1

syn P=1&ring 3 و معنا -.P=0.2014 20°C -10.09 - 3.3 kw 4+ Stale( P,-0.2MNA, TI = 20°C) from pressure fasle, At p=0.2 Mina, Tear = -10.09°c Tr> Tsar i fence stale Ouperheated state from superheated farle, hi = 267.78 ls/ks Af state2 (P = 1.8 une To = 1050 c) from superheated farce h₂ 333.25 lglies At states (P=18mpe, a=0) from pressure lashes 142.22 hoahol 3.3 = n(haha) 3-3 (333.25 - 267.28) 0.0004 resp m ure fasce, you Heat removed sy Isrne condenser (Sort) = in (h₂ h₂) Sort At state 6 (P = 0.2 Nng, x=1) from pressure talle 2413 lug ho = hel 0-2M na -0.050yX(333.25-142-22) 9.6288 low Heat required by water heater me at hy = (mare) = (200X06001)x 109 x 42 x (55-20) 29400 les han hinho = hiz why ho Chicho) a hua 142022 – (267.78 - 2413) - hy = 115.74 chy 294ou lg huchs = 115-74 laste time = gaus 9.6288 (19) BO53.33 see 50.889 minutes (In Heat pump, as desired effect- Cory is ufilised